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this to find out the shortest path for various nodes
this to find out the shortest path for various nodes-this is to find out the shortest path for various nodes
- 2022-02-03 14:28:49下载
- 积分:1
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CRC_FIC檢查CRC碼
CRC_FIC檢查CRC碼 計算CRC碼
檢查程式的CRC碼算法
CRC_FIC檢查CRC碼 計算CRC碼
檢查程式的CRC碼算法
CRC_FIC檢查CRC碼 計算CRC碼
檢查程式的CRC碼算法
- 2023-02-25 02:20:03下载
- 积分:1
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Clustering objects on subsets of attributes
Clustering objects on subsets of attributes - COSA - a subspace clustering algorithm.-Clustering objects on subsets of attributes- COSA- a subspace clustering algorithm.
- 2022-02-14 17:21:45下载
- 积分:1
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有趣的小程序(螺旋矩阵输出)
有趣的小程序(螺旋矩阵输出)-interesting little (Spiral matrix output)
- 2023-03-08 21:05:03下载
- 积分:1
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elliptic partial differential equation algorithm applied to solving rectangular...
二阶椭圆偏微分方程的差分算法,适用于求解矩形区域,任意边界条件。-elliptic partial differential equation algorithm applied to solving rectangular region, arbitrary boundary conditions.
- 2022-04-25 13:57:58下载
- 积分:1
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离散正弦变换程序
离散正弦变换程序-discrete sine transform procedures
- 2023-09-03 14:40:03下载
- 积分:1
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a description of the problem is : No. 1, 2, ..., n n clockwise direction by indi...
约瑟夫问题的一种描述是:编号为1,2,…,n的n个人按顺时针方向围坐一圈,没人持有一个密码。一开始人选一个正整数作为报数上限值m,从第一个人开始按顺时针自1开始报数,报到m是停止报数。报m的人出列,将他的密码作为新的m值,从他在顺时针方向上的下一个人开始重新从1报数,如此下去,直至所有人全部出列为止。-a description of the problem is : No. 1, 2, ..., n n clockwise direction by individuals sitting around a circle, no one holding a password. One person started as a positive integer limits on the number of reported m, from the first individuals to embark on the clockwise from a few reportedly started, the report m is reportedly stopped a few. M reported out of the list of his password as a new value m, from a clockwise direction in the next re-started from a newspaper a few, like that, until the total of all listed so far.
- 2022-02-03 16:31:48下载
- 积分:1
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用C++写的矩阵和矢量运算库
用C++写的矩阵和矢量运算库-C write the matrix and vector arithmetic library
- 2023-01-20 04:05:04下载
- 积分:1
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serial port
这个解释有点复杂和晦涩。我们的
- 2023-07-22 03:20:03下载
- 积分:1
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code to solve 8-queens problem
- 2022-03-18 08:23:55下载
- 积分:1