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MP3编码解码
这个是PC端实现MP3编解码,通过浮点型double类型,实现比较复杂!
- 2023-07-05 07:20:03下载
- 积分:1
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线性方程迭代法,下载的顶一下哦
线性方程迭代法,下载的顶一下哦-Linear equations iterative method, download the top click oh
- 2022-11-01 13:05:03下载
- 积分:1
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算断裂的,可以试试。QMG2.0 is written by
S. Vavasis (and others mentioned in src files)...
算断裂的,可以试试。QMG2.0 is written by
S. Vavasis (and others mentioned in src files) and is copyrighted (c)
1999 by Cornell University.-Operator faults, you can try. QMG2.0 is written byS. Vavasis (and others mentioned in src files) and is copyrighted (c) 1999 by Cornell University.
- 2022-01-27 17:07:10下载
- 积分:1
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最短小的dvd解码程序
最短小的dvd解码程序-shortest small DVD decoding procedures
- 2022-03-05 07:14:10下载
- 积分:1
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计算机编程,用C语言计算改进的欧拉算法的典型题目
计算机编程,用C语言计算改进的欧拉算法的典型题目-Computer programming, using C language to improve the calculation of the Euler algorithm for a typical subject
- 2023-05-10 04:15:03下载
- 积分:1
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基本算法为:先将1填入第一行中间位置;再依次将2
基本算法为:先将1填入第一行中间位置;再依次将2-n方按如下规律填写://1,填入上个数上一行的右边位置,如果没有上一行则转到最后一行,如果右边没有方格//则转到最左边的方格。2,如果要填的位置上已经有数,则转填到它上一个数的下边方格//3,对于第一行的最后一个数的下一个数应填在该数下边的空格处-basic algorithm : a first Enter the middle of the first line; Another will be followed by 2-n-law filled out as follows :// 1, the number entered on the right side on his position, if not in his will to the last line, if not right box// then transferred to the most left while the box. 2, to fill the position of several, in turn, to fill it on a number of subordinate box// 3, the first trip to the final a few under a few should fill in the blank space of a few top candidate Department
- 2022-02-05 03:13:23下载
- 积分:1
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算法设计与分析 哈夫曼树及哈夫曼编码 贪心算法
一个记录字符及出现频率的文件如下所示:huffman.haf7a,45b,13c,12d,16e,89f,34g,20试编写一个读取此种格式文件类CHuffman, 内部机制采用优先队列,用于建立Huffman树及进行Huffman编码输出,其用法可以如下所示: CHuffman hm("hu
- 2022-03-10 07:52:22下载
- 积分:1
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哥德巴赫猜想:哥德巴赫(哥德巴赫)曾提出这样一个猜想:2000以内…
Goldbach s conjecture: Goldbach(哥德巴赫)曾经提出了一个这样的猜想: 对于2000 以内的正偶数都能够分解为两个素数之和。 要求: 该题是一个猜想,我们不去证明它,而是通过编程序来验证 该猜想是否正确。 输入: 用户从键盘任意输入一个自然数。 输出: 给出满足猜想的两个自然数。-Goldbach conjecture : Goldbach (Goldbach) had raised such a guess : 2000 within the can is even divided into two prime numbers and. Requirements : The title is a guess, we do not prove it, but through programmed to verify the guess is correct. Input : arbitrary user input from the keyboard to a natural number. Output : meet guess is the natural number two.
- 2023-05-19 07:45:03下载
- 积分:1
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based on a DCT domain of digital watermarking system examples
一个基于DCT变换域的数字水印系统实例-based on a DCT domain of digital watermarking system examples
- 2022-04-21 14:57:25下载
- 积分:1
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CF 基于用户
协同过滤,英文名Collaborative 滤波
- 2022-08-22 11:05:58下载
- 积分:1