机器人足球进攻策略的仿真研究

可以把一图形的投影中心线找出来,我本科论文就做过那玩意-A graph can find out the centerline of the projector, I did undergraduate thesis on那玩意

一款工程FFT的计算，包括非常详细的开发文档。 里面有经典的关于复数的算法。-FFT calculation of a project, including the development of very detailed documentation. There are classic on the complex algorithms.

蚁群算法的源代码，里面有详细的实现过程，有很好的参考价值-Ant colony algorithm source code, which the realization of the process in detail, have a good reference value

一个计算圆周率的自编程序（带原码）。可以计算40000位以内的圆周率。经过充分优化，速度非常快。 开发平台：turbo-pascal 7.0， 嵌入汇编。-a calculation of the ratio of circumference wrote (with the original code). 40,000 can be calculated within the pi. After full optimization, speed very quickly. Platform : turbo-pascal 7.0, embedded in the compilation.

资源描述根据货运量形成的原因，分析了货运量和相关影响因素之间的关系以及货运量预测的特点，在此基础上，建立货运量预测的广义回归神经网络(General Regression Neural Network,GRNN)模型，并以我国某年的货运量和相关经济指标的历史统计数据作为学习样本，通过拟合训练和外推预测分析，验证了GRNN用于货运量预测的有效性.

％96年中国大学生数学建模竞赛A题:捕鱼-96% of university students in China Mathematical Contest in Modeling A theme : fishing

蚁群算法(ant colony optimization, ACO)，又称蚂蚁算法，是一种用来在图中寻找优化路径的机率型算法。它由Marco Dorigo于1992年在他的博士论文 请点击左侧文件开始预览 ！预览只提供20%的代码片段，完整代码需下载后查看 加载中 侵权举报

This algorithm was developed by Professor Ronald L. Rivest of MIT and can be found presented in several languages. What I provide to you here is a C++ derivative of the original C implementation of Professor Rivets. The library code itself is platform-independant and has been tested in Redhat Linux. I ve included the sample code and makefile that I used for the Linux test. The demo, however, was written with Visual C++ 6 on a Windows 2000 platform.-This algorithm was developed by Professor Ronald L. Rivest of MIT and can be found presented in several languages. What I provide to you here is a C derivative of the original C implementation of Professor Rivets. The library code itself is platform-independant and has been tested in Redhat Linux. I ve included the sample code and makefile that I used for the Linux test. The demo, however, was written with Visual C 6 on a Windows 2,000 platform.

应用背景就是leetcode上面第四题，找到两个排序的数组的中位数。就是leetcode上面第四题，找到两个排序的数组的中位数。就是leetcode上面第四题，找到两个排序的数组的中位数。就是leetcode上面第四题，找到两个排序的数组的中位数。关键技术变异的二分查找吧。变异的二分查找吧。变异的二分查找吧。变异的二分查找吧。变异的二分查找吧。变异的二分查找吧。变异的二分查找吧。变异的二分查找吧。变异的二分查找吧。

快速排序和冒泡排序-rapid sequencing and Bubble Sort