Well seismic tomographic imaging applications by VC++

利用c++编写的矩阵迭代算法，其中包含了雅可比方法和高斯-赛德尔方法-Use c++ Matrix prepared iterative algorithm, which contains the Jacobi method and Gauss- Seidel method

给出了c语言面试、等级考试、上级考试等各类编程算法题，包括常用语法及算法。适合初学者应对考试时题海复习。掌握全面的c语言编程知识锻炼能力。

这是VC迷宫的代码，写的很整洁，非常的好，下载了即使可以用，声音什么的没有设置

n皇后问题的进阶解法，算法简单，注意输入的N可能没有解，比如2-n Queen of the intermediate solution, the algorithm is simple, pay attention to the N input may not solved, such as the two

一个正整数的集合S，c是一个正整数，在s的子集中判断是否存在子集和为c的子集-A set of positive integers S, c is a positive integer, in the subset of s, to determine whether there is a subset of a subset of and for the c

数组排序的经典程序shell。-Sorting an array of classic shell procedures.

资源描述本代码根据APROORI算法和MapReduce特点，将Apriori算法在Hadoop平台上并行化，通过并行化可以使Apriori算法处理大量的数据而不受单机运算能力的限制。

0 / 1背包问题是一个N P-复杂问题，为了解决该问题，，将用回溯算法解决该问题。既然想选择一个对象的子集，将它们装入背包，以便获得的收益最大，则解空间应组织成子集树的形状（如图1 6 - 2所示）。该回溯算法与4 . 2节的装载问题很类似。首先形成一个递归算法，去找到可获得的最大收益。然后，对该算法加以改进，形成代码。改进后的代码可找到获得最大收益时包含在背包中的对象的集合。-0/1 knapsack problem is a P-complex issues, in order to solve the problem, and will be used backtracking algorithm to solve the problem. As to the choice of a subset of object, they will load a backpack, in order to obtain the greatest profits, the solution should be organized into space subset of the shape of the tree (Figure 1 6-2 below). The backtracking algorithms and 4. Two loading problem is very similar. Forming a recursive algorithm to get the maximum benefit available. Then, this algorithm is modified to form code. Improved code can be found at the maximum benefits included in the backpack of a collection of objects.

大约有10种排序方法，如堆排序、快速排序、归并排序、插入排序、外壳排序、选择排序、早泡排序、线性排序、地址选择排序和基排序。我自己提出了一种简化的快速排序。-about 10 species of sequencing methods, such as heap sort, quick sort, merge, in order to insert sequencing, shell sort, select, in order of ranking as foam, linear ordering, sequencing and address choice-based ranking. I propose a simplified Quick Sort.

#include   #include   #include   #include   #include   #include   using namespace std;   int deep,n;   int v[1005]={1};   int h(int top)   {       int k=deep-top;       int x=v[top];   请点击左侧文件开始预览 ！预览只提供20%的代码片段，完整代码需下载后查看 加载中 侵权举报