基于VC++的典型数字信号处理

sift算法  采用opencv，VC++实现  值得借鉴

k-means 算法的工作过程说明如下：首先从n个数据对象任意选择 k 个对象作为初始聚类中心；而对于所剩下其它对象，则根据它们与这些聚类中心的相似度（距离），分别将它们分配给与其最相似的（聚类中心所代表的）聚类；然后再计算每个所获新聚类的聚类中心（该聚类中所有对象的均值）；不断重复这一过程直到标准测度函数开始收敛为止。-k-means algorithm process as follows: First of all, the object data from the n choose k object as initial cluster centers and the remaining for the other object, then according to their cluster center with those of the similarity (distance) respectively assigned to them with the most similar (represented by cluster center) clustering obtained and then calculated for each new cluster center clustering (all objects in the cluster mean) repeated this process until the standard measure of function until the beginning of convergence.

用差分方法求解沃尔泰拉方程，此处为一个变元的方程，由于该方程同时含有微分和积分，一般求解有一定的困难。-use of the finite difference method for Volterra equation here as a variable element of the equation, As the same time contain differential equations and integral, the general solution is definitely difficult.

FDTD计算光子晶体组成的波导通路的场传播-FDTD calculation of photonic crystal waveguide consisting of field dissemination pathways

用于评价图像分割的精度，包括单个物体的相对错误率指标，和标记错误率。-used to evaluate the accuracy of image segmentation, including individual objects relative error rate indicators, and marking error rate.

c语言版斗地主程序包括如何洗牌、发牌、排序、出牌、胜负的算法

(Genetic Algorithm Based K-means algorithm, related program and algorithm description.)

它显示了选择、交叉和变异。这是遗传算法的操作。该算法主要适用于自然选择过程“优胜劣汰”.

奇数N 阶魔方阵问题： 奇数N 阶魔方阵的构造规则如下： 1、在第一行的正中间填入1； 2、如果左上角能够移动，则往左上角填入后继的数；如果左上角不 能移动，则顺移到该列最下方左边的一列中最靠近该列的位置； 3、如果左上角不能移动，同时在该列位置的最下方左边最靠近的位 置处也不能填入数，则往该位置的上一行的最右边的位置处填入 后继数； 4、每次尽可能地往左上角填数，如果发现左上角已经填满了数，则 从当前填的数的位置下方填上后继数。 要求： 无。 输入： 用户从键盘任意输入一个正奇数。 输出： 打印出该魔方阵。-odd N bands Demon Lineup : N-odd magic Lineup Construction Rules are as follows : 1, the first line is the middle of a preference; Two, if the upper left corner to Mobile, the successor to fill in the upper left; If the upper left corner, unable to move, with the move out of the bottom of the left one of the closest out of position; three, if the upper left corner, unable to move, while in the position shown in the bottom left nearest location Department has not entered a few, to the position of the party on the right side of the positions filled successor; 4, each possible to fill the upper left corner, if fill the upper left corner, has found a few, from the current fill several positions to fill in the bottom subsequent few. Requ

中国象棋源代码，使用Visual c++编写，对喜欢象棋的朋友，可以研究一下算法，具有很好的参考价值~