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Huffman
霍夫曼编码实验报告,内含源代码,编码原理
(Huffman coding lab report, containing the source code, coding theory)
- 2011-06-04 20:44:25下载
- 积分:1
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hellow4
序列二次规划算法,能求解包含约束和无约束的问题,非常方便。(Sequential quadratic programming algorithm to solve constrained and unconstrained contain the problem, very convenient.)
- 2021-01-08 18:18:51下载
- 积分:1
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Hash-table
哈希表
数据结构课程设计
1.1问题描述
针对自己的班集体中的“人名”设计一个哈希表,使得平均查找长度不超过R,完成相应的建表和查表程序。
1.2基本要求
假设人名为中国姓名的汉语拼音形式。待填入哈希表的人名共有30个,取平均查找长度的上限为2。构造哈希函数,用链表法处理冲突。
1.3测试数据
读取熟悉的30个人的姓名作测试。(Hash table
Data Structure Course Design
1.1 Description of the problem
For their own class group of the "names" to design a hash table, making the average search length does not exceed R, the completion of construction of tables and look-up table corresponding procedures.
1.2 Basic requirements
Assuming the name of the person called Chinese pinyin form. To be filled into a hash table names a total of 30, taking the average search length of the upper limit of 2. Construct a hash function, treatment with a list of conflict.
1.3 Test Data
Read the familiar names of 30 individuals tested.)
- 2011-12-19 15:39:00下载
- 积分:1
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american_heritage
USACO中的American heritage,用C++编写,运用了树的遍历知识(the American heritage of USACO, with C++ prepared, using a tree traversal knowledge)
- 2013-07-21 18:31:10下载
- 积分:1
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BDX
设计、编写和调试面向对象C++程序,实现任意两个同类数据比大小
的通用函数(模板),涵盖普通数值型数据之间的比较、两个字符串之间的比较
(按字典序)、两个复数之间的比较(按模大小)等,并通过主函数加以调用和
测试。(Design, writing and debugging of object-oriented C++ procedures to achieve similar data than the size of any two generic functions (template), covering general comparison between numerical data, the comparison between the two strings (lexicographically), two Comparison between complex numbers (modulo the size), and through the main function to be invoked and tested.)
- 2020-11-28 13:49:29下载
- 积分:1
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class
给定m个n维向量a , a , ,am 1 2 ,向量分类问题要求将相同的向量划分为同一类。试用
抽象数据类型表设计解向量分类问题的有效算法。(Given m a n-dimensional vector a, a,, am 1 2 )
- 2008-05-05 22:03:41下载
- 积分:1
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crox
矩形件最优排样的程序,用Visual C编写,在6.0下能正常运行。(Rectangular pieces Optimal Nesting program)
- 2013-05-13 14:31:41下载
- 积分:1
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tudebianli
图的遍历问题 数据结构 C C++ 源码 课程设计
严蔚敏版的书(yrteryryer)
- 2010-05-08 09:24:06下载
- 积分:1
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ds3
单向链表的创建与操作
设单向链表中节点的数据域的数据类型为整型,编写函数实现以下操作:
(1)实现单向链表的创建(包括初始化)与输出操作,节点的个数及节点的数据由用户输入。
(源代码:ds3-1.c)
(2)查找给定的单链表中的第i个节点,并将其地址返回。若不存在第i个节点,则返回空地址。
(源代码:ds3-2.c)
(3)查找给定的单链表中值为n的节点,并将其地址返回。若不存在值为n的节点,则返回空地址。同时,还应通过参数传回该节点的序号。
(源代码:ds3-3.c)
(4)删除给定的单链表中的第i个节点,成功返回1,失败返回0。
(源代码:ds3-4.c)
(5)删除给定的单链表中值为n的节点,成功返回1,失败返回0。
(源代码:ds3-5.c)
(6)在给定的单链表的第i位上插入值为n的节点。
(源代码:ds3-6.c)
(7)在给定单链表的值为m的节点的前面插入一个值为n的节点。
(源代码:ds3-7.c)
(Creation and operation of a one-way linked list
Set up a one-way linked list data type node integer data fields , write a function to achieve the following:
( 1 ) achieve the creation of a one-way linked list ( including initialization ) and output operation , the number of nodes and node data entered by the user .
( Source : ds3-1.c)
( 2 ) Find a single list given in the i-th node and returns its address . Without the presence of the i-th node , returns an empty address.
( Source : ds3-2.c)
( 3 ) Find a given node in a given value of n single list , and return address . Without the presence of the value of n nodes , returns an empty address. Meanwhile, the number should be returned by the parameters of the node .
( Source : ds3-3.c)
( 4 ) Delete the given singly linked list in the i-th node , the successful return 1, else return 0 .
( Source : ds3-4.c)
( 5 ) to delete a single node in the list is given n , the successful return 1, else return 0 .
( Source : ds3-5.c)
( 6 ) )
- 2014-05-11 19:19:41下载
- 积分:1
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Joseph
说明: 约瑟夫问题,四种解法,分别是静态链表,顺序表两种和循环链表(Joseph problems, the four solution, namely a static list, order form and the cycle of two lists)
- 2010-04-23 08:20:53下载
- 积分:1