xianxingbiao

二叉树的操作，涉及到三种顺序的遍历，树的凹入表示法，转化为一维数组储存，节点的计数，以及中序线索化。(Binary operation, involving three kinds of the order of traversal, tree concave representation into a one-dimensional array of storage, the node count, as well as in the threaded sequence.)

简单的迷宫问题，有点土，还望大家多指点指点，在此感激不尽。(????? mad spasm, ? Tang Gao, ? oligonucleotide ??? Ning Ning ? ?, Hitomi ?????.)

c++ data struct stack

魔方问题 数据结构 使用c++ 经典问题(Cube problem Data Structure Using c++ Classic problem)

通过c语言数组算法解决josephus问题，m个人围成一圈，从第一个小孩开始顺时针方向每数到第n个小孩时这个小孩离开，最后剩下的小孩是胜利者。求第几个小孩为胜利者(C language array algorithm to solve the Josephus problem, m individual circle, from the first child began to count clockwise every n children, the child left, and finally the remaining child is the winner. A few kids for victory)

二叉树排序，二叉树的递归调用排序，属于C语言源码(Binary Tree Sort)

东北大学数据结构实验指导书,2014级东北大学软件学院软件工程专业(Experimental data structure, guide books, Northeastern University, Northeastern University School of Software 2014 Software Engineering)

说明：  贪心方法是一种改进了的分级处理方法。它首先根据题意，选取一种量度标准。然后按这种量度标准对这n个输入排序，并按排序一次输入一个量。如果这个输入和当前已构成在这种量度意义下的部分最优解加在一起不能产生一个可行解，则不把此解输入加到这部分解中。这种能够得到某种度量意义下的最优解的分级处理方法称为贪心方法。(greedy method is an improvement of the classification methods. According to its first title Italy, and a selection of standards of measurement. Then, under such a standard measure of this sort n input, with an input an order volume. If the input current and constitutes a measure of significance in this part of the optimal solution together not produce a feasible solution. this solution will not put this added to the importation of decomposition. This can be a meaningful measure of the optimal solution hierarchical method, known as greedy method.)

利用二叉平衡树进行数据排序。这里采用的数据结构是指针。(The use of balanced binary tree sort the data. The data structure used here is a pointer.)

参加运动会的 个学校编号为 。比赛分成 个男子项目和 个女子项目，项目编号分别为 和 。由于各项目参加人数差别较大，有些项目取前五名，得分顺序为7，5，3，2，1；还有些项目只取前三名，得分顺序为5，3，2。写一个统计程序产生各种成绩单和得分报表。 2、要求产生各学校的成绩单，内容包括各校所取得的每项成绩的项目号、名次（成绩）、姓名和得分；产生团体总分报表，内容包括校号、男子团体总分、女子团体总分和团体总分。 3、测试数据：对于 ， ， ，编号为奇数的项目取前五名，编号为偶数的项目取前三名，设计一组实例数据。 (The school serial number participating in Games is. Competition divides into men s event and women s event , the project serial number parts for the sum. The difference is bigger since every project participates in a number , some projects choose the first five , score order is 7 , 5 , 3 , 2 , 1 Still have some of projects taking the first three places , score only being 5 , 3 , 2 in proper order. Write a form for report counting procedure producing the various school report card and score. 2, demands the school report card producing every school , content includes every achievement project number , position in a name list (achievement) , full name and score per got by school Produce the group total points form for report , content including the school number , male person group total points , woman group total points and group total points. 3, testing data: Be that the odd number project chooses the first five to the serial number, the serial number is that the even number project c)