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migong---cPP

于 2011-11-03 发布 文件大小:8KB
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代码说明:

  迷宫问题C++代码。。。解决迷宫问题。。。。(Maze C++ code. . . Solve maze problems. . . .)

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  • CR17_2014.05.19_list
    数据结构线性表教学笔记,内容讲基础知识,没基础可以看看(Linear table data structure teaching notes, basic knowledge content says, no base can take a look)
    2014-06-09 23:35:37下载
    积分:1
  • yuyundonghui
    参加运动会的 个学校编号为 。比赛分成 个男子项目和 个女子项目,项目编号分别为 和 。由于各项目参加人数差别较大,有些项目取前五名,得分顺序为7,5,3,2,1;还有些项目只取前三名,得分顺序为5,3,2。写一个统计程序产生各种成绩单和得分报表。 2、要求产生各学校的成绩单,内容包括各校所取得的每项成绩的项目号、名次(成绩)、姓名和得分;产生团体总分报表,内容包括校号、男子团体总分、女子团体总分和团体总分。 3、测试数据:对于 , , ,编号为奇数的项目取前五名,编号为偶数的项目取前三名,设计一组实例数据。 (The school serial number participating in Games is. Competition divides into men s event and women s event , the project serial number parts for the sum. The difference is bigger since every project participates in a number , some projects choose the first five , score order is 7 , 5 , 3 , 2 , 1 Still have some of projects taking the first three places , score only being 5 , 3 , 2 in proper order. Write a form for report counting procedure producing the various school report card and score. 2, demands the school report card producing every school , content includes every achievement project number , position in a name list (achievement) , full name and score per got by school Produce the group total points form for report , content including the school number , male person group total points , woman group total points and group total points. 3, testing data: Be that the odd number project chooses the first five to the serial number, the serial number is that the even number project c)
    2009-04-07 22:40:37下载
    积分:1
  • Circlist_Josephus3_4
    循环链表的应用 循环链表的应用 很方便的实现(cycle Chain cyclic chain of convenience Implementation)
    2006-11-23 19:36:47下载
    积分:1
  • xianxingbiaolianjie
    线性表的链接实现可利用单链表来实现,每个节点存储一个元素。 利用单链表来实现线性表的元素的插入,删除,修改等功能。 (Linear link table can be used to achieve a single linked list to implement, each node stores an element. Using a single linked list to implement elements of the linear table insert, delete, modify, and other functions.)
    2011-04-26 11:57:25下载
    积分:1
  • dxsjjc
    多项式加减乘 用数据节够得算法实现多项式的加减乘 原理简单易懂(suoxiangshi jiajiancheng)
    2009-12-29 11:13:13下载
    积分:1
  • Numbersequence
    说明:  简单的数据结构算法 在POJ上的题目 利用C++实现(Simple data structure algorithm in POJ on the subject using C++ Implementation)
    2010-05-04 19:03:45下载
    积分:1
  • paixu
    实现冒泡,快速,希尔排序法。并计算,比较他的次数。(Achieve bubbling fast shell sort. And calculate, compare the number of times.)
    2012-05-21 22:13:12下载
    积分:1
  • ANT
    A*算法通过启发式探索下一结点,逐步逼近目标结点,且使得路径最短。(A* algorithm heuristic to explore the next node, and gradually approaching the target node, and that the shortest path.)
    2012-05-17 09:14:21下载
    积分:1
  • test12
    约瑟夫问题,用数据结构的循环链表实现约瑟夫问题的解答(Joseph problems,30 people in a circle, and inspires us with a circular chain to said. Can use structure array to make a cycle chain. The structure has two members, one for pointing down a pointer to a circular chain )
    2012-05-14 10:29:52下载
    积分:1
  • jose
    约瑟夫环(约瑟夫问题)是一个数学的应用问题:已知n个人(以编号1,2,3...n分别表示)围坐在一张圆桌周围。从编号为k的人开始报数,数到m的那个人出列;他的下一个人又从1开始报数,数到m的那个人又出列;依此规律重复下去,直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1,最后结果+1即为原问题的解。 (Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)
    2015-01-09 17:28:41下载
    积分:1
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