Four-bracket-operator

约瑟夫问题，通过C语言对约瑟夫问题进行了分析和讲解，从而解决问题(Joseph problems, by Joseph C language issues are analyzed and explained, in order to solve the problem)

常在该网站下载资料，也想分享些材料上去，这个资料是FRFT算法(Often the site to download information, but also want to share some material up, this information is FRFT algorithm)

效验算法单循环链表，这些都是实用经典的算法和数据结构(Well-tested algorithm round robin list, these are practical classic algorithms and data structures)

基于数据结构的图书管理系统，基本功能都有，可以拿来作为数据结构的课程设计(Based library management system data structures, basic function, can be used as a data structure of the curriculum design)

算法课程设计 分治法解决循环赛日程表 源代码+word报告+答辩PPT(Curriculum design of divide and conquer algorithm to solve a round robin schedule report+ source code+ word reply PPT)

链栈 对于堆栈stack的链式实现 应用指针(linked stack)

数据结构作业－停车场管理(operating data structure-the car park management)

简单的迷宫问题，有点土，还望大家多指点指点，在此感激不尽。(????? mad spasm, ? Tang Gao, ? oligonucleotide ??? Ning Ning ? ?, Hitomi ?????.)

本文讨论了动态规划这一思想的核心内容和其基本特点，探讨了动态规划思想的适用范围，动态规划子问题空间和递推关系式确立的一般思路。(This paper discusses the dynamic planning this thought core content and its basic characteristics, this paper discusses the dynamic planning idea, the applicable scope of the dynamic programming problem space and son recursive formula of the establishment of general thoughts. )

冒泡优化： 如果一个序列是int n[]={1,2,3,4,5,6,7,8,9} , 用正常的冒泡排序需要排8次才行，优化之后1次就好，也就是说序列越接近于正常序列，改进之后的冒泡排序的次数就越少，这样会给一个冒泡排序算法带了很大的效率。 思想：添加一个boolean变量用来判断冒泡是否是已经排好了顺序，如果boolean的值为false，说明是已经排好了，如果boolean的值true，说明没有排好，继续排。(If a sequence is int n [] = {, 1,2,3,4,5,6,7,8,9} need to row 8 times the job after optimization times like normal bubble sort, but alsomeans that the sequence is more close to the normal sequence, improved bubble sort, the less the number, which would give a bubble sort algorithm with a great deal of efficiency. Idea: add a boolean variable used to determine the bubble whether it is already lined up the order, if the boolean is false, indicating already lined up, if the boolean value of true, did not line up, continue to row.)