Monkeys-and-peach

用链表解决约瑟夫问题。 约瑟夫环是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。 其中包括一个实验报告，介绍了编程思路和输出结果截图。(List to resolve Joseph. Josephus is the application of a mathematical problem: Given n individuals (numbered 1, 2, 3, ... n, respectively) sitting around a round table around. From number k people began to count off the number to m the man out of the line his next person and from a number off, the man was out of the line number to m so regularly repeated down until roundtable around of the people all of the columns. Including a lab report describes the programming ideas and output screenshots.)

堆栈实现C++,以VC++环境为准——逍遥大洋至上(The stack of the C++, VC++ environment will prevail)

各种数据结构代码,欢迎下载,里面有JAVA,C,C++等等各种版本(Data structure and code, please download)

说明：  用从c＋＋写的floyd最短路径算法，可以求邻接矩阵任意两点的最短路径。(from using c++ to write the Floyd shortest path algorithm, can help adjacency matrix arbitrary 2:00 Shortest Path.)

关于随机发牌算法的小程序，作为数据结构的大作业，开发环境是VC(Random licensing algorithm for small procedures, as big job data structures, the development environment is VC)

约瑟夫问题，通过C语言对约瑟夫问题进行了分析和讲解，从而解决问题(Joseph problems, by Joseph C language issues are analyzed and explained, in order to solve the problem)

数据挖掘中聚类算发中基于密度的算法DBSCAN(Hair count data mining clustering algorithm DBSCAN density-based)

总结了10种排序的方式。用代码加以实现。(the ten way of Line up a preface)

数据结构中，运用链表实现四则括号运算等，运行在VC控制台上。(Data structure, the use of chain operations to achieve four brackets, etc., running in the VC console.)

/*快速排序：以待排序元素中的第一个元素作为基准将带排序的元素分为三组 *大于基准元素为一组置于基准值的右边，小于基准值的元素为一组置于基准值的左边， *基准值为一组，这样就找到了基准元素的位置就确定了 *如此递归调用。直到每一组的low==high，即实现了排序的要求。 */ (/* Rapid Sort: the first element to be sorted in the element as a basis with with sorting the elements are divided into three groups* is greater than the reference element of a group is placed on the right side of the reference value, smaller than the reference value elements for a group of placed on the left side of the reference value,* reference value, a group, so that the location of the reference element is found it is determined* so recursive call. Until each group of low == high to achieve the requirements of the sort.* /)