-
joseph
用链表解决约瑟夫问题。
约瑟夫环是一个数学的应用问题:已知n个人(以编号1,2,3...n分别表示)围坐在一张圆桌周围。从编号为k的人开始报数,数到m的那个人出列;他的下一个人又从1开始报数,数到m的那个人又出列;依此规律重复下去,直到圆桌周围的人全部出列。
其中包括一个实验报告,介绍了编程思路和输出结果截图。(List to resolve Joseph. Josephus is the application of a mathematical problem: Given n individuals (numbered 1, 2, 3, ... n, respectively) sitting around a round table around. From number k people began to count off the number to m the man out of the line his next person and from a number off, the man was out of the line number to m so regularly repeated down until roundtable around of the people all of the columns. Including a lab report describes the programming ideas and output screenshots.)
- 2012-08-27 22:37:52下载
- 积分:1
-
LStack
堆栈实现C++,以VC++环境为准——逍遥大洋至上(The stack of the C++, VC++ environment will prevail)
- 2012-03-26 08:35:26下载
- 积分:1
-
code
各种数据结构代码,欢迎下载,里面有JAVA,C,C++等等各种版本(Data structure and code, please download)
- 2010-06-22 11:11:45下载
- 积分:1
-
最短路径c++语言
说明: 用从c++写的floyd最短路径算法,可以求邻接矩阵任意两点的最短路径。(from using c++ to write the Floyd shortest path algorithm, can help adjacency matrix arbitrary 2:00 Shortest Path.)
- 2020-09-20 14:07:55下载
- 积分:1
-
Fa_Pai
关于随机发牌算法的小程序,作为数据结构的大作业,开发环境是VC(Random licensing algorithm for small procedures, as big job data structures, the development environment is VC)
- 2014-10-16 17:54:20下载
- 积分:1
-
yuesefu
约瑟夫问题,通过C语言对约瑟夫问题进行了分析和讲解,从而解决问题(Joseph problems, by Joseph C language issues are analyzed and explained, in order to solve the problem)
- 2011-10-26 10:56:33下载
- 积分:1
-
DBSCAN
数据挖掘中聚类算发中基于密度的算法DBSCAN(Hair count data mining clustering algorithm DBSCAN density-based)
- 2011-09-29 09:53:45下载
- 积分:1
-
yu992324
总结了10种排序的方式。用代码加以实现。(the ten way of Line up a preface)
- 2010-07-29 09:41:07下载
- 积分:1
-
Four-bracket-operator
数据结构中,运用链表实现四则括号运算等,运行在VC控制台上。(Data structure, the use of chain operations to achieve four brackets, etc., running in the VC console.)
- 2011-12-12 10:51:31下载
- 积分:1
-
fast_sort
/*快速排序:以待排序元素中的第一个元素作为基准将带排序的元素分为三组
*大于基准元素为一组置于基准值的右边,小于基准值的元素为一组置于基准值的左边,
*基准值为一组,这样就找到了基准元素的位置就确定了
*如此递归调用。直到每一组的low==high,即实现了排序的要求。
*/
(/* Rapid Sort: the first element to be sorted in the element as a basis with with sorting the elements are divided into three groups* is greater than the reference element of a group is placed on the right side of the reference value, smaller than the reference value elements for a group of placed on the left side of the reference value,* reference value, a group, so that the location of the reference element is found it is determined* so recursive call. Until each group of low == high to achieve the requirements of the sort.* /)
- 2012-10-26 21:42:43下载
- 积分:1