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mataqipan
马踏棋盘的贪心算法,8*8棋盘,基本上不用回溯。(horse riding chessboard of the greedy algorithm, 8* 8 chessboard, basically not retroactive.)
- 2006-05-30 20:05:17下载
- 积分:1
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Lists
用模板实现了单向链表的增删改查等功能,并且适用于多种数据结构和类,简单实用,是学习和使用的绝好资料(Template to achieve a one-way linked list CRUD functions, and is suitable for a variety of data structures and classes, simple and practical, is to learn and use excellent information)
- 2014-06-02 13:36:32下载
- 积分:1
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KMP---MFC
数据结构里面的KMP算法的可视化演示程序 MFC实现(Visualization of data structures inside the KMP algorithm demo program MFC implementation)
- 2020-07-04 08:40:01下载
- 积分:1
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Lecture7
数据结构中插入排序,堆栈排序等的用法还有希尔排序(Data structure insertion sort, stack, sort, etc. use well sorted Hill)
- 2011-07-27 15:31:31下载
- 积分:1
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Online_RandMarkingAlgorithm
本程序解决的是:模拟类似计算机主、缓存的存储结构,当用户请求某个页面时,若某个页面已在缓存中,则直接从缓存中去取,不会产生失误(即未在缓存中命中),否则,就到主存中去取,代价变大。
本程序采用随机标记算法,即在在线标记算法的基础上,对于替换页面时,采用随机从未标记的缓存项中选出一项进行替换。
代码、文档详尽(Addressed in this program are: analog computer-like main, cache storage structure, when the user requests a page, a page in the cache directly from the cache to fetch, does not produce errors (that is, not in the cache in the hit), otherwise, to the main memory to fetch a consideration of larger. This program uses a random marking algorithm, online marking algorithm based on random never mark the cache entry selected a replacement for the replacement page. Code, documentation detailed)
- 2012-09-19 13:01:47下载
- 积分:1
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HuffanCoding
读取数据,统计所得到的文件中每个字母的权值,创建哈夫曼树,哈夫曼编码。哈夫曼解码,解码后内容写入到指定的文件。
读取数据里面的内容是由英文单词组成。读取文件的时候传入文件存放的路径、读取方式以及读出以后存放的数组,最终可以得到一个存放目标文件内容的数组。
将得到的数组进行字母权值的统计,统计每个字母出现的次数,次数即为每个字母的权值。
将得到的字符数组与权值数组作为创建哈夫曼树的依据,哈夫曼树根据每个字母权值的大小来创建,每个节点,包括权值、父节点、左子、右子和字母本身。
根据哈夫曼树进行编码。形成目标文件的哈夫曼编码,将此编码返回。
根据哈夫曼树得到的数组即为解码数组,解码数组作为解码的结果返回。
写入输出文件,将解码得到的数组、文件的完整路径以及文件的写方式作为参数传入,将数组写入到相应的文件中。
(Read the data, statistical documents obtained weights for each letter, create a Huffman tree, Huffman coding. Huffman decoding, the decoded contents are written to the specified file.
Read the content inside is composed of English words. When the incoming file to read the file storage path, read mode and read out after storage array that can eventually get a storage target file contents of the array.
The resulting array of letter weights statistics, statistical number of occurrences of each letter, the number is the weight of each letter.
The resulting character array with the weights array as the basis for creating Huffman tree, Huffman tree based on the size of the weights of each letter to create, for each node, including weights, parent, left child, right child, and letter itself.
According to Huffman coding. The formation of the target file Huffman coding, this code returns.
According to Huffman decoding the resulting array is an array, the decoder decodes the result is retur)
- 2020-07-02 15:40:01下载
- 积分:1
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StringClass
这个代码是STRING类的声明及实现,因为我认为C++类库中的string类比较庞大,找一个函数需要很长时间,所以用一个简单明了的代替之.(STRING kind of statement and realized, because I think the C library string of relatively large, a function for a very long time. Therefore, the use of a simple and straightforward replaced it.)
- 2006-05-17 17:46:58下载
- 积分:1
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qiuhe
多项式求和,用链表实现的一元多项式求和程序,比较 靠谱(Polynomial sum, with the linked list implementation of a polynomial summation procedure, more reliable)
- 2011-09-15 09:16:38下载
- 积分:1
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ds3
单向链表的创建与操作
设单向链表中节点的数据域的数据类型为整型,编写函数实现以下操作:
(1)实现单向链表的创建(包括初始化)与输出操作,节点的个数及节点的数据由用户输入。
(源代码:ds3-1.c)
(2)查找给定的单链表中的第i个节点,并将其地址返回。若不存在第i个节点,则返回空地址。
(源代码:ds3-2.c)
(3)查找给定的单链表中值为n的节点,并将其地址返回。若不存在值为n的节点,则返回空地址。同时,还应通过参数传回该节点的序号。
(源代码:ds3-3.c)
(4)删除给定的单链表中的第i个节点,成功返回1,失败返回0。
(源代码:ds3-4.c)
(5)删除给定的单链表中值为n的节点,成功返回1,失败返回0。
(源代码:ds3-5.c)
(6)在给定的单链表的第i位上插入值为n的节点。
(源代码:ds3-6.c)
(7)在给定单链表的值为m的节点的前面插入一个值为n的节点。
(源代码:ds3-7.c)
(Creation and operation of a one-way linked list
Set up a one-way linked list data type node integer data fields , write a function to achieve the following:
( 1 ) achieve the creation of a one-way linked list ( including initialization ) and output operation , the number of nodes and node data entered by the user .
( Source : ds3-1.c)
( 2 ) Find a single list given in the i-th node and returns its address . Without the presence of the i-th node , returns an empty address.
( Source : ds3-2.c)
( 3 ) Find a given node in a given value of n single list , and return address . Without the presence of the value of n nodes , returns an empty address. Meanwhile, the number should be returned by the parameters of the node .
( Source : ds3-3.c)
( 4 ) Delete the given singly linked list in the i-th node , the successful return 1, else return 0 .
( Source : ds3-4.c)
( 5 ) to delete a single node in the list is given n , the successful return 1, else return 0 .
( Source : ds3-5.c)
( 6 ) )
- 2014-05-11 19:19:41下载
- 积分:1
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111
八皇后问题,用C语言实现,在VC++6.0环境中可以运行!92种答案(Eight queens problem)
- 2012-06-18 21:02:54下载
- 积分:1