DLinkedList

百鸡算法是一种简单的逻辑算法，通过不同的鸡不同的价钱，得出大鸡小鸡的个数(Typical code for white chicken algorithm)

讲述数据机构的图论部分和程序设计的关系，适合学习算法的同学学习阅读，很不错的一本书。(Graph theory algorithm and programming)

一、 地理数据文件应用 对由点、线、面构成的地理数据文件进行打开、读取、关闭操作。 要求： 1、在C++环境下，通过程序设计实现文本格式数据文件的操作； 2、在打开数据文件后，生成点、线、面三个链表，分别用于记录三种类型的数据。 3、数据文件结构说明 (Geographic data file applications by point, line, surface consisting of geographic data file open, read, and close operations. Requirements: in C++ environment, through the program design text format data file operations 2, open the data file, generate points, lines, surfaces three linked list, respectively, for the record three types of data. 3, a data file structure)

本实验设有一个线性表，分别实现数组结构存储的原地逆置。为数据结构课程必做实验。(This experiment has a linear form, respectively, to achieve the storage array structure in situ reverse home. For the data structure courses will do the experiment.)

任务：实现Dijkstra算法 工程名：Project_ShortestPath 要求：实现Dijkstra算法，算法主体写在CGraph类中；要求是从command窗口中输入源节点编号，并在command窗口中输出从源节点到所有目的节点的最短路长及最短路。注：要输出整条路径，而不仅仅是前一跳，也不允许逆序输出。 (Task: Dijkstra' s algorithm to achieve the project name: Project_ShortestPath requirements: achieve Dijkstra algorithm, the algorithm written in the body CGraph class requires input from the command window, the source node number, and in the command window, all of the output from the source node to the destination node shortest long and the shortest. Note: To export the entire path, not just before the jump, do not allow reverse output.)

数据结构课上老师布置的5个小项目的源代码，分别是汽车过河，一元多项式，迷宫，日历，BFS_DFS(failed to translate)

C语言实现井字棋博弈的过程，采用极大极小算法。(The C language game of tic-tac-toe chess, using the minimax algorithm.)

说明：  可以实现判断二叉树是否为完全二叉树、判断两棵二叉树是否镜像对称、求一棵二叉树的一个最长枝等功能(Can determine whether the binary tree is complete binary tree to determine whether two binary mirror symmetry, one of the longest seeking a binary tree branches and other functions)

POJ 字符串的插入 可以将一定长度的字符串插入之前给出的字符串之中(POJ string can be inserted into a length of string into a string before being given)

迷宫问题C++代码。。。解决迷宫问题。。。。(Maze C++ code. . . Solve maze problems. . . .)