xianduan

数据结构课程作业，查找算法。用哈希算法下实行查找(Data structure course work, search algorithm. Under the hash algorithm used to find)

航迹起始中的逻辑航迹起始算法源代码，本代码具有很好的航迹起始效果！ (Track initiation logic for track initiation algorithm source code, this code has the effect of track initiation)

说明：  进程死锁.资源分配图的绘制 建立所需数据结构；  使用题目21存成的资源分配图的文件作为输入；  编写资源分配图化简算法；  每化简一步，在屏幕上显示化简的当前结果；  最后给出结论，是否死锁，如思索给出死锁的进程及资源； (Process deadlock. Resource allocation mapping  establish the required data structures  Use title 21 deposit into resource allocation graph file as input  writing resource allocation map simplification algorithm  Each simplification step, on-screen display simplification of the current result  Finally, the conclusion of a deadlock, deadlock is given as thinking processes and resources )

说明：  用链表的方式实现多项式的加减，其中结构体包含幂次和系数。(Polynomial addition and subtraction with a list of ways in which the structure and contains the power of coefficients.)

说明：  贪婪算法的简单描述 不过没做完 只是想下个程序 用用。。。。 (greed math)

堆栈实现C++,以VC++环境为准——逍遥大洋至上(The stack of the C++, VC++ environment will prevail)

数据结构中，运用链表实现四则括号运算等，运行在VC控制台上。(Data structure, the use of chain operations to achieve four brackets, etc., running in the VC console.)

一、 地理数据文件应用 对由点、线、面构成的地理数据文件进行打开、读取、关闭操作。 要求： 1、在C++环境下，通过程序设计实现文本格式数据文件的操作； 2、在打开数据文件后，生成点、线、面三个链表，分别用于记录三种类型的数据。 3、数据文件结构说明 (Geographic data file applications by point, line, surface consisting of geographic data file open, read, and close operations. Requirements: in C++ environment, through the program design text format data file operations 2, open the data file, generate points, lines, surfaces three linked list, respectively, for the record three types of data. 3, a data file structure)

背包算法的c++简单实现，很有用的，可以看看(Knapsack algorithm)

迷宫求解一般采用“穷举法”，逐一沿顺时针方向查找相邻块（一共四块－东(右)、南(下)，西(左)、北(上)）是否可通，即该相邻块既是通道块，且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)