abc

迷宫求解一般采用“穷举法”，逐一沿顺时针方向查找相邻块（一共四块－东(右)、南(下)，西(左)、北(上)）是否可通，即该相邻块既是通道块，且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)

c语言的一些小李子，初学c的朋友有帮助，主要有顺序表、二分查找、二叉树、单链表等等(Some Survival Song c language, c beginner to help a friend, there are sequence tables, binary search, binary tree, a single linked list, etc.)

C常用算法程序集，一些C语言的基本算法在里面都可以找到。(this is a very good book about c language,you will find it is very useful in your work.)

一个简单的停车场管理程序,是初级学习数据结构时的一个十分重要的实验,了解这个对学习堆栈十分有用,基本题目是 设有一个可以停放[size=10.5pt]N[size=10.5pt]辆汽车的狭长的停车场，[size=10.5pt] [size=10.5pt]它们有一个大门可以供车辆进出。车辆按到达停车场时间的先后次序从停车场最里面向门口处停放（最先到达的第一辆车停在停车场的最里面）。如果停车场已放满[size=10.5pt]N[size=10.5pt]辆车，则后来的车辆只能在停车场大门外的便道上等待，一旦停车场内有车开走，则排在便道上的第一辆车就可进入停车场。停车场内如果有某辆车要开走，在它之后进入停车场的车辆都必须先退出停车场为它让路，待其开出停车场后，这些车辆再依原来的次序进入。每辆车在离开停车场时，根据它在停车场内停留时间的长短交费。如果停在便道上的车辆未进入停车场就要离去，允许其离去时不收停车费，并且仍然保持在便道上等待的车辆的次序()

本系统采用C语言编写，利用邻接链表实现最短路径问题，关键路径问题等(The system uses the C language, using adjacency list realize the shortest path problem, critical path issues)

数据结构中图的遍历Data structure traversal of center(Data structure traversal of center)

采用邻接矩阵实现有向网的存储，建立有向网，并实现单源最短路径算法。(The realization of the use of adjacency matrix to the network storage, the establishment of the network, and to achieve single-source shortest path algorithm.)

几个比较好的初级算法，初学者可以看一下思想，对算法入门(A few good elementary algorithms, beginners can look at thinking on algorithms entry)

电梯模拟，实现一个模拟电梯的环境，用C程序实现的，封装良好(elevator modify)

说明：  分别用堆栈和数组的方法实现任何进制的数制转换(Arrays were used to stack and method of implementation of any binary number system conversion )