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该代码实现了深拷贝的问题，对于深拷贝进行了一系列的介绍，并且显示其与浅拷贝的区别。(A deep copy of the code issues a series of deep copy for presentation, and shows the difference between a shallow copy.)

参加运动会的 个学校编号为 。比赛分成 个男子项目和 个女子项目，项目编号分别为 和 。由于各项目参加人数差别较大，有些项目取前五名，得分顺序为7，5，3，2，1；还有些项目只取前三名，得分顺序为5，3，2。写一个统计程序产生各种成绩单和得分报表。 2、要求产生各学校的成绩单，内容包括各校所取得的每项成绩的项目号、名次（成绩）、姓名和得分；产生团体总分报表，内容包括校号、男子团体总分、女子团体总分和团体总分。 3、测试数据：对于 ， ， ，编号为奇数的项目取前五名，编号为偶数的项目取前三名，设计一组实例数据。 (The school serial number participating in Games is. Competition divides into men s event and women s event , the project serial number parts for the sum. The difference is bigger since every project participates in a number , some projects choose the first five , score order is 7 , 5 , 3 , 2 , 1 Still have some of projects taking the first three places , score only being 5 , 3 , 2 in proper order. Write a form for report counting procedure producing the various school report card and score. 2, demands the school report card producing every school , content includes every achievement project number , position in a name list (achievement) , full name and score per got by school Produce the group total points form for report , content including the school number , male person group total points , woman group total points and group total points. 3, testing data: Be that the odd number project chooses the first five to the serial number, the serial number is that the even number project c)

说明：  链表逆转,实现单链表的逆转程序，数据结构(List Inverse)

数据结构中，运用链表实现四则括号运算等，运行在VC控制台上。(Data structure, the use of chain operations to achieve four brackets, etc., running in the VC console.)

八皇后算法，用的是最简单的穷举法，在VC++6.0上编写的。(Eight Queens algorithm, using the simplest method of exhaustion, in VC++6.0 written on.)

说明：  操作系统先来先服务调度算法模拟（C描述）(Operating a first-come first-served scheduling simulation (C description))

说明：  有助于c++的初学者在平日的学习中更好的学习(Contribute to better learning c++ beginners learning on weekdays)

自己编写的floyd 最短距离求解程序。实用简单。gcc (Floyd shortest distance to write your own solver. Practical and simple. gcc)

队列的一般数据结构 队列的创建 删除 修改 取数据等等(The general data structure queue queue to take the data and so create delete modify)

一道poj上的问题的解答，棋盘上的距离问题。即实现棋盘上从一个点移动到王，后，兵之间最短步数的解答。(A poj answers to your questions on the chessboard distance problem. That is, move from one point to the king on the board, after the shortest number of steps between the soldiers answer.)