LR(0)

说明：  ACM及各类基本算法模板，包括数据结构，计算几何，字符串，图论，数学，高精度等许多常用模板(ACM basic algorithm and various templates, including data structures, computational geometry, string, graph theory, mathematics, high-precision, and many other commonly used templates)

KD树算法，能够实现对点云数据进行压缩，非常简单，适用于初学者(KD tree algorithm, can achieve the point cloud data compression, very simple, suitable for beginners)

编程 主范式 使用真植表 用栈的应用 使用了 后缀表达式 (biancheng zhu fanshi)

设计一个表达式求值的程序。该程序必须可以接受包含（，），+，-，*，/的中缀表达式，并求出结果。如果表达式正确，则输出表达式的结果；如果表达式非法，则不输出或输出其他字符。(Design an expression evaluation procedures. The program must accept (,), including +, -, *, / the infix expression, and the results obtained. If the expression is correct, the output of the expression is output; if the expression is illegal, no other characters are output or exported.)

冒泡优化： 如果一个序列是int n[]={1,2,3,4,5,6,7,8,9} , 用正常的冒泡排序需要排8次才行，优化之后1次就好，也就是说序列越接近于正常序列，改进之后的冒泡排序的次数就越少，这样会给一个冒泡排序算法带了很大的效率。 思想：添加一个boolean变量用来判断冒泡是否是已经排好了顺序，如果boolean的值为false，说明是已经排好了，如果boolean的值true，说明没有排好，继续排。(If a sequence is int n [] = {, 1,2,3,4,5,6,7,8,9} need to row 8 times the job after optimization times like normal bubble sort, but alsomeans that the sequence is more close to the normal sequence, improved bubble sort, the less the number, which would give a bubble sort algorithm with a great deal of efficiency. Idea: add a boolean variable used to determine the bubble whether it is already lined up the order, if the boolean is false, indicating already lined up, if the boolean value of true, did not line up, continue to row.)

快速排序，用数组的存储结构，实现数的排序。共有八组随机数据，还能够计算出每组数据的处理时间，最终得到平均时间。(Quicksort array storage structure, to achieve the sort of number. A total of eight sets of random data, but also be able to calculate the processing time of each data, and eventually obtain the average time.)

vb实现的排序算法演示vb实现的排序算法演示.冒泡、选择、折半等多种排序算法(vb sort demodemodemodemodemovb sort demodemodemodemodemo)

约瑟夫环（约瑟夫问题）是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1，最后结果+1即为原问题的解。 (Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)

说明：  任意给定输入的一个小写英文字符串a1a2a3…an-1an (n≥5) 输出：字符串Ana1An-1a2An-2a3…A2an-1A1an,其中Ai为ai的大写形式 例如，输入aybdx，则递归程序输出XaDyBbYdAx (Any given input of a lowercase string a1a2a3 ... an-1an (n ≥ 5) Output: the string Ana1An-1a2An-2a3 A2an-1A1an, which Ai ai uppercase for example, input aybdx recursive program output XaDyBbYdAx)

使用全排列实现hash，看看吧相信对大家会有些帮助的(Full array hash)