11组表达式求值

多项式求和，用链表实现的一元多项式求和程序，比较 靠谱(Polynomial sum, with the linked list implementation of a polynomial summation procedure, more reliable)

带权有向以及无向图的各种操作，适合数据结构初学者使用，是图那一章的重点(belt and the right to have no plans to the various operations, data structure suitable for beginners, is the chief focus of the chapter)

校园导航系统包含佛山科技学院本部校区的校园景点平面图。通过系统的各功能不仅可以查询任意景点的编号，名称，简介等信息，还可以查询任意两景点间的最短路径及长度和所有路径及长度。另外，还可以通过一系列操作增加，更改或删除任意的景点的各信息。(Contains the campus attractions plan of the campus Foshan Institute of Technology campus navigation system. Through the function of the system not only can query any spots number, name, profile and other information, can also query the shortest path and arbitrary length between two spots and all paths and the length of. In addition, can also increase through a series of operations, the information change or delete any of the attractions.)

自己用c语言写的一个模块化多电平最近电平调制排序的c程序，希望对大家有帮助(Own use c language written in a modular multi-level modulation level recently sort of c program, we hope to help)

PKU ONLINEJUDGE 2371

简单的一个链栈.即用链表实现的一个栈。可以做简单的插入、删除、查找等操作(this is a simple C++ program )

二叉树的建立 中序遍历二叉树 把二叉树转换成双向链表(Binary tree in the establishment of traversing Binary conversion to binary tree into a doubly linked list)

VC游戏编写中的求解最短路径算法源码，本示例是自动寻径演示，篮点是起点，红点是终点，按确定键开始。源码爱好者注：编译后运行的时候请把EXE文件从Debug目录中拷贝到项目根目录中，若不然会出错。 (The preparation of the VC games to solve the shortest path algorithm source code, in this example is the automatic routing demonstration, the basket is the starting point, the red dot is the end point, press the OK button to start. Source enthusiasts Note: When compiled and run, please copy the EXE file from the Debug directory to the root directory of the project, and if not be wrong.)

2008软件公司面试题:排序大全：简单选择排序、冒泡排序、选择排序、shell排序、快速排序、插入排序、堆排序(从小到大)、归并排序（利用递归）(2008 software companies face questions: Sort Guinness: simple choice to sort, bubble sort, select sort, shell sort, quick sort, insert sort HEAPSORT (from small to large), Merging Sort (recursive))

约瑟夫环，数据结构算法，挺有意思，看看，看看(ysphdfgfgf)