-
examples-of-data-structure
吴伟民版数据结构每个算法的c实现方法,并模块化处理,将各个功能分开编程,有助于移植使用(failed to translate)
- 2013-05-06 13:20:48下载
- 积分:1
-
cPP
数据结构课设,城市地铁站的设计与使用规划(Set data structure class, subway station design and use of planning)
- 2011-07-03 11:58:24下载
- 积分:1
-
yuesefuhuan
使用VC编写的约瑟夫环程序,简单明了,方便使用(Prepared using the VC Joseph Central program, simple and clear, easy to use)
- 2009-09-08 16:45:26下载
- 积分:1
-
001
二叉树的中序遍历,先序遍历以及后序遍历的算法(Binary tree in preorder traversal, preorder traversal and postorder traversal algorithm)
- 2012-06-03 23:26:44下载
- 积分:1
-
xunhuansaiqxf
算法课程设计 分治法解决循环赛日程表 源代码+word报告+答辩PPT(Curriculum design of divide and conquer algorithm to solve a round robin schedule report+ source code+ word reply PPT)
- 2010-05-26 23:51:17下载
- 积分:1
-
0728-0708-0704
北邮数据结构课程设计大作业之旅行模拟查询系统。可实现多线程多旅客、中途更改计划、动态显示旅客状态等多个需求。已通过验收。(BUPT curriculum design travel query system simulation of large operations. Multithreading enables passengers to change plans midway, dynamic display multiple demands guest status. It has passed inspection.)
- 2021-03-14 12:09:23下载
- 积分:1
-
Fund6-StringViewer
字符串,实现了文件中查找想要的字符串,并将其标记出来
- 2010-12-26 20:51:45下载
- 积分:1
-
maze
迷宫求解一般采用“穷举法”,逐一沿顺时针方向查找相邻块(一共四块-东(右)、南(下),西(左)、北(上))是否可通,即该相邻块既是通道块,且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)
- 2013-12-13 17:55:45下载
- 积分:1
-
Task1-trial--10211281--zly
描述:足球俱乐部包括球员、普通行政人员。球员有姓名、年龄、能力、年薪、转会费、进球总数、服役年限等重要参数;普通行政人员有姓名、年龄、能力、年薪等参数。你需要给相关管理机构开发一个管理程序,实现对众多足球俱乐部管理的基本功能。具体功能包括:
a) 俱乐部的增删改查,俱乐部的属性包括名称、现金、其下人员;
b) 可以对所有球员的各项属性进行简单搜索,支持输入多个条件,条件之间用&&连接,例如:
i. “年龄不大于25且服役年限大于5年且进球数大于100的球员”,查询表达式:!(@age>25) && @experience>5 && @kick>100
c) 支持球员在不同俱乐部间的买卖,买卖需符合以下条件:作为买方的俱乐部的现金>=球员的转会费,交易完成后,卖方将得到转会费。
要求:
d) 必须采用面向对象的方式,使用类组织数据结构,并注意类的继承关系;
e) 在题目要求基础上可以自行扩展功能,提供扩实用扩展功能者适当加分(加分不超过5分)。
(Description: Football club including players, general administrative staff. Player name, age, ability, salary, transfer fee, total number of goals, service life and other important parameters ordinary administrative staff name, age, ability, salary and other parameters. You need to give the relevant management agencies to develop a management program to achieve the number of football club management s basic functions. Specific features include:
a) the club CRUD, the name of the club s property, including cash, under which personnel
b) all players can perform a simple search of the property, supports input multiple conditions with && connection between conditions, for example:
i. "Age is not greater than 25 and greater than 5 years service life and goals more than 100 players," query expression:! (@ age> 25) && @ experience> 5 && @ kick> 100
c) Support the players traded between different clubs, the sale subject to the following conditions: As a buyer s club cash> = pl)
- 2013-08-20 10:09:29下载
- 积分:1
-
stack
数据结构 堆栈 实现了以下功能:
cout<<"----------------主菜单---------------"<<endl
<<"* 1.建立 *"<<endl
<<"* 2.输出 *"<<endl
<<"* 3.判断栈是否为空 *"<<endl
<<"* 4.栈的长度 *"<<endl
<<"* 5.输出栈顶元素 *"<<endl
<<"* 6.进栈 *"<<endl
<<"* 7.出栈 *"<<endl
<<"* 8.遍历 *"<<endl
<<"* 9.数制转换 *"<<endl
<<"* 10.清空 *"<<endl
<<"* 11.销毁 *"<<endl
<<"* 12.退出 *"<<endl
<<"--------------------------------------"<<endl<<endl (data structure stack)
- 2013-11-01 11:05:10下载
- 积分:1