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Monkeys-and-peach
Monkeys and peach,Monkeys and peach(Monkeys and peach)
- 2013-09-01 22:06:42下载
- 积分:1
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Fa_Pai
关于随机发牌算法的小程序,作为数据结构的大作业,开发环境是VC(Random licensing algorithm for small procedures, as big job data structures, the development environment is VC)
- 2014-10-16 17:54:20下载
- 积分:1
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LINK
建立链表的算法:
新节点链入表尾建立链表:
动态分配第一个节点变量;
用指针head 妥善保存链表第一个节点的地址值;
依次动态分配一个新节点变量;
将上一个节点的指针域指向新生成的节点;
循环3),4)步骤,直到所有节点均连入链表;
将最后一个节点的指针域赋值为0;
(Establish the list of algorithms:
The new node links footer build list:
Dynamic allocation of the first node variable
Keep the list head pointer of the first node address value
In order to dynamically allocate a new node variable
The domain of a node pointer to the new generation of nodes
Cycle 3), 4) step, until all nodes are connected to the chain
Pointer field will last node assigned to 0 )
- 2015-01-05 16:03:48下载
- 积分:1
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jgctgu
流水线车间的零件加工排序问题,以达到最优的加工顺序,使加工时间最短或零件后期维护费用最少(Plant parts processing pipeline scheduling problem, in order to achieve optimal machining sequence, so that the processing time of the shortest or least parts later maintenance costs)
- 2014-05-08 01:12:54下载
- 积分:1
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eitTableParse
该程序分析eit表的数据结构,病输出相应内容信息(parse eit table and output content info)
- 2016-05-22 17:52:42下载
- 积分:1
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bfs
这是BFS算法的实现。用C语言实现的。好好学习吧。(This is achieved BFS algorithm. Implemented using C language. Learn it.)
- 2013-12-05 15:56:50下载
- 积分:1
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BeiDa_ACM1702
北大ACM1702题 转换为3进制
很经典(NULL)
- 2009-12-08 11:31:40下载
- 积分:1
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sf_2014320164457
数据结构中的许多东西,包括头文件、例题、习题等等(Data structure many things, including the header files, examples, exercises, etc.)
- 2014-04-03 15:24:34下载
- 积分:1
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b-trees
① 实现在B-树上的查找,并分析其时间复杂性。
② 实现B-树的ADT,包括其上的基本操作:结点的加入和删除。
③ 要求B-树结构中的M=3 或5,实现其中的一种即可。
④ 实现基本操作的演示。
(4) 实现提示
(b-trees c/c++)
- 2021-01-20 09:48:41下载
- 积分:1
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Huffman-Tree
使用三叉链表实现的哈夫曼树,统计inputfile1.txt中各字符的出现频率,并据此构造Huffman树,编制Huffman 码;根据已经得到的编码,对01形式的编码段进行译码。
具体的要求:
1.将给定字符文件编码,生成编码,输出每个字符出现的次数和编码;
2.将给定编码文件译码,生成字符,输出编码及其对应字符。
(Emergence of the frequency of each character in the trigeminal lists using the Huffman tree, statistics inputfile1.txt, and accordingly the Huffman tree structure, preparation of Huffman code according to the coding has been. 01 to form the code segment for decoding.
Specific requirements:
1 coding the given character file, generating the encoding, and outputting the number and encoding of each character
2 will be given the encoding file decoding, generating the character, the output code and its corresponding character.)
- 2015-05-22 15:37:03下载
- 积分:1