myfndr

bpsk qam gmsk fsk modulation function

说明：  STBC，经典Alamouti 2X2 空时编码(Alamouti 2X2 STBC)

生成4阶M序列的matlab程序，这是一个function函数，应用时在matlab上输入一个初始向量(Generation 4 order M series of matlab program, this is a function function, application in matlab input a initial vector)

完整的OFDM自适应资源分配仿真程序，OFDM.m为主程序，修改发送和接受天线数量可实现MIMO OFDM仿真。(Complete OFDM Adaptive resource allocation simulation program, OFDM.m the main program, modify the number of transmit and receive antennas to achieve MIMO OFDM simulation.)

一个关机恶搞程序，仅供娱乐，其实很简单就用了system函数(A spoof shutdown procedures, for entertainment purposes only, is actually very simple to use system functions)

基于小波基的StOMP算法，用于压缩感知(StOMP algorithm based on wavelet for compressive sensing)

matlab+C language spea2

Floyd最短路径算法，任意找出两点的最短距离，C语言代码。(Floyd shortest path algorithm, and find out the most short of any two points, C language code. )

The Frequency Domain Decomposition (FDD) is an output-only system identification technique popular in civil engineering, in particular in structural health monitoring. As an output-only algorithm, it is useful when the input data is unknown. FDD is a modal analysis technique which generates a system realization using the frequency response given (multi-)output data

自己写的用Matlab模拟一个缓冲区大小（包括正在服务的那个）为10的随机排队系统。 （1）到达过程是的泊松过程（到达速率为Mu），服务时间服从独立指数分布（均值为1/Lamda）。 对Mu//Lamda=0.2，Mu//Lamda=0.8和Mu//Lamda=1.1三种情况进行仿真，求出队列中接受服务用户为n的概率P(n), n=0,...,10。并与理论结果进行比较。 （2）假设到达过程为均匀过程（到达速率为Mu），服务时间服从独立瑞利分布（均值为1/Lamda）。(yourself writing a simulation using Matlab buffer size (including services that are) for the following 10 Machine queuing system. (1) arrival process is the Poisson process (arrival rate of Mu), submit to independent service index distribution (mean of 1/Lamda). Right Mu// Lamda = 0.2, Mu// Lamda = 0.8 and the Mu// = 1.1 Lamda three of the simulation, Queue calculated users receive services n the probability P (n), n = 0 ,..., 10. And with the theoretical results. (2) It is assumed that the arrival process for the uniform process (arrival rate of Mu), submit to independent service Rayleigh distribution (mean of 1/Lamda).)