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complex algorithm
复数运算详细算法-complex algorithm
- 2022-02-07 16:21:29下载
- 积分:1
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连通域提取算法
这个是纯C写的连通域提取算法,速度和效率相对较快,在算法中采用了八领域的关系来确定是否是同一个连通域,有用的朋友可以自行下载,可以用于自己的工程当中。
- 2022-01-25 20:14:52下载
- 积分:1
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给出了分形计算生成动态树的VC++源代码。生长出来的树摇曳而逼真。...
给出了分形计算生成动态树的VC++源代码。生长出来的树摇曳而逼真。-Gives the fractal calculation generate dynamic tree VC source code. Grow trees swaying and realistic.
- 2022-09-07 18:15:02下载
- 积分:1
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6个关于逼近与拟合的C源程序,有示例,来自《C语言数值计算常用程序》,所以程序均经本人测试可用!...
6个关于逼近与拟合的C源程序,有示例,来自《C语言数值计算常用程序》,所以程序均经本人测试可用!-six approximation with the fitting of the C source code, examples, from the "C language commonly used numerical procedures," and so I have been put to test available!
- 2023-09-07 17:15:02下载
- 积分:1
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It is about a named set partition of the source code is a set partition problem...
它是关于一个命名集分区的源代码,是集分区问题中的一个acm
- 2023-06-01 19:40:03下载
- 积分:1
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vc下的一个仿matlab界面的矩阵运算程序,其中单独封装的矩阵类可实现大多数常用矩阵运算功能,经常被我单独拿来使用...
vc下的一个仿matlab界面的矩阵运算程序,其中单独封装的矩阵类可实现大多数常用矩阵运算功能,经常被我单独拿来使用-vc under an imitation of Matlab interface matrix calculation procedures, which separate package matrices can be used to achieve the majority of matrix calculation functions, I was often alone using them
- 2022-04-12 20:05:14下载
- 积分:1
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Gaze tracking/ pupil tracking /eye tracking
提出了一个实时的视线追踪方案。程序可运行,追踪效果好。
An eye tracker gives the pixel position of the center of the pupil in an image whereas a gaze tracker determines where the person is looking on the screen.
↩
Timm and Barth. Accurate eye centre localisation by means of gradients. In Proceedings of the Int. Conference on Computer Theory and Applications (VISAPP), volume 1, pages 125-130, Algarve, Portugal, 2011. INSTICC.
- 2022-07-07 14:42:01下载
- 积分:1
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一个公平的经验,农历和男性的经验
支持公历、农历及公历转农历使用公式法(不是查表法)的日历控件,完全自主开发。- A fair experience, the lunar calendar and the male experience
transfer the lunar calendar use formula law (is not Zha Biaofa) the
calendar controls, completely independently develops.
- 2023-05-04 12:35:02下载
- 积分:1
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哈夫曼编码和解码系统,并可对文件进行编码
哈夫曼编码和解码系统,并可对文件进行编码-Huffman coding and decoding system, the documents can be encoded
- 2022-04-10 18:08:36下载
- 积分:1
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输入一个长整数,不使用字符转换,检查是否为对称数, 是显示 TRUE,否显示FALSE....
输入一个长整数,不使用字符转换,检查是否为对称数, 是显示 TRUE,否显示FALSE.-Enter a long integer, do not use character conversion, check whether the symmetry is to show TRUE, any signs FALSE.
- 2022-03-26 04:53:36下载
- 积分:1