图形学算法演示程序

糊涂先生给他的五个朋友写信，他写了五封信，但是当他的朋友收到信后，都告诉他：“你的信寄错了”。那么请你计算一下：出现这种情况的概率有多少？（假设糊涂先生是随机地往信封里装信的），你能不能把所有的情况都列出来呢？-confused to his five friends in a letter he wrote five letters, but when his friend received the letter, had told him : "You sent a letter wrong." Then you do some calculations : this happens the probability is the number? (Assuming confused is randomly installed to envelope the letter), you can put all the cases listed?

计算负载使用牛顿拉夫逊法 method.case ieee14 节点系统的流量。

FPGA实现DFT快速算法-FPGA DFT Fast Algorithm

列句25宫的所有组合。 每行,每列,和对角线 数字和为25。-sentence of 25 out of all the combinations Palace. Each line, each and diagonal figures and 25.

用对分法求非线性方程f(x)=0的实根.基本思想：逐步缩小这个有根的区间，当这个区间长度减小到一定程度是，就取这个区间的中点作为根的近似值-Use of sub-method of nonlinear equation f (x) = 0 the real roots. The basic idea: to gradually narrow the range of this well-established, when the interval length decreases to a certain extent, we take the midpoint of this range as the root approximation

此代码程序解决当然人工智者。用C++编程语言，并采用广度优先搜索方法遍历所有图形，并找到可能的路径此代码。

MD5/SHA-1摘要生成算法-MD5/SHA-1 Abstract Algorithm

有很多文章放在网上，提供更多有关免疫算法比资料覆盖在本导言中。一些链接如下，但谷歌搜索"人造一词 免疫系统"会带来更多。本文论述了一些主要概念包括克隆选择、 亲和力成熟和抗体相互作用的免疫算法。

实现时间序列建模的marple算法，具体操作程序里有提示-Achieve time-series modeling marple algorithm, specific procedures have prompted

矩阵的最大特征值的幂法. 对于工程计算而言，矩阵的特征值和特征向量都是相当重要和常见的数据，这里给出的幂法是一种常见的求解方法，用的是迭代的思想。 符号说明: 1A为待求的矩阵， 2Uk，Vk为迭代用的列向量。 3最后的最大特征值maxLamda由最后一次的max(Uk)-----求Uk中的绝对值最大的元素的绝对值.所决定。 而maxLamda所对应的特征向量由最后一次迭代的Vk所决定. 主要的想法就是先选一个不为0的初始向量U0!=0，然后按下面的式子迭代。 -matrix eigenvalue of the largest power France. For engineering calculation, Matrix eigenvalues and eigenvectors are very important and common data, here is the power law is a common solution, using the iterative thinking. Symbol : 1A of the question for the matrix, 2Uk, Vk iteration of the column vector. The final three largest eigenvalue maxLamda from last max (uk Hoffmann for the uk the largest absolute value of the absolute value of the element. by decision. While maxLamda corresponding eigenvectors from the last iteration of Vk decision. The main idea was first choice not one of the initial vector 0 U0! = 0, then by the following formula iteration.