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数学建模
数学建模-公交车调度问题论文(维普阅读器)-mathematical modeling-bus scheduling problem thesis (Wei-pu readers)
- 2022-09-14 09:25:03下载
- 积分:1
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牛顿插值方法的计算机实现程序
牛顿插值方法的计算机实现程序-Newton interpolation method of computer procedures
- 2023-01-09 17:30:03下载
- 积分:1
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Prolog实现8-puzzle
he 8-puzzle will be represented by a 3x3 list of lists positions where the empty box will be represented by the value 9, as shown below: [[9,1,3],[5,2,6],[4,7,8]]
Possibility Solution: Only half of the initial positions of the 8-puzzle are solvable. There is a formula that allows to know from the beginning if you can solve the puzzle.To determine whether an 8-puzzle is solvable, for each square containing a value N is calculated how many numbers less than N there after the current cell. For example, to the initial status
- 2023-07-26 11:40:02下载
- 积分:1
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一个比较通用的大数运算库,内附安装说明,5_4_2版本
一个比较通用的大数运算库,内附安装说明,5_4_2版本-A relatively large numbers of common computing library, containing installation instructions, version 5_4_2
- 2022-07-11 14:29:16下载
- 积分:1
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cc1100send-and-receive
P1DIR |= 0x03; //P1_0, p1_1, OUTPUT
CLKCON &= ~0x40; //晶振
while(!(SLEEP & 0x40)); //等待晶振稳定
CLKCON &= ~0x47; //TICHSPD128分频,CLKSPD不分频
SLEEP |= 0x04; //关闭不用的RC振荡器
//Initkey();
Init_T1();
InitUART(9600); //初始化串口
请点击左侧文件开始预览 !预览只提供20%的代码片段,完整代码需下载后查看 加载中 侵权举报
- 2022-03-23 14:42:43下载
- 积分:1
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java程序实现的通俗易懂的二分查找的算法源代码
java程序实现的通俗易懂的二分查找的算法源代码-java program to achieve the user-friendly dichotomous search algorithm source code
- 2022-08-18 10:42:39下载
- 积分:1
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plane eight
平面8节点单元类,可以输出单元的刚度、质量、阻尼矩阵,并可通过形函数插值得到内部各点得位移、应力等。对各位以前编写的程序的一个补充和完善吧。-plane eight-unit category, the output unit stiffness, mass, damping matrix, through the shape function can be interpolation points in the internal displacement and stress. Right before you and the procedure for the preparation of a supplement and perfect it.
- 2023-02-03 03:45:04下载
- 积分:1
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基于小波变换的圆形 Hough 变换的蓄能器图像计算
此代码计算的蓄能器图像基于小波变换的圆形 Hough 变换,给定一个的半径。
- 2022-01-25 18:20:14下载
- 积分:1
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科学与工程数值算法求解方程组的类
科学与工程数值算法求解方程组的类-science and engineering numerical algorithm for solving equations of the type
- 2022-03-13 20:51:02下载
- 积分:1
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ACM区域赛2011年大连G题
题意:
给出一些子串,和母串的长度,问在母串里面包含任意子串的最大值是多少,
其中每个子串最多只能被计算一次。如果最大值为负数,则输出特定的字符串。
sample:
input:
2 4
ATG 4
TGC -3
1 6
TGC 4
4 1
A -1
T -2
G -3
请点击左侧文件开始预览 !预览只提供20%的代码片段,完整代码需下载后查看 加载中 侵权举报
- 2022-03-26 07:39:27下载
- 积分:1