C++人员信息管理

C#编写的Guass消去法-C# prepared by the Gauss elimination method

111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111

这是改进的欧拉算法源码-This is an improved Euler algorithm source code

快速排序！ 经典的算法。 provides methods to sort a set of objects with quicksort algorithm.-rapid sequencing! The classical algorithm. Provides methods to sort a set of objects with quicksort algorithm.

一直以来对 SVPWM 原理和实现方法困惑颇多， 无奈现有资料或是模糊不清， 或是错误百 出。 请点击左侧文件开始预览 ！预览只提供20%的代码片段，完整代码需下载后查看 加载中 侵权举报

Program can deal with MDL lasers for remote firing and reading output of distnace

latent dirichlet allocation C语言实现算法 LINUX 下运行-latent dirichlet allocation the c implementation

一维搜索程序――黄金分割点方法，我自己编的！大家多多下载，多多支持啊！-one-dimensional search procedures-- Golden Section point, I developed! Members can download the generous support ah!

mps create

数值积分算法实现对一阶微分方程组的计算：通过编写程序语言，运用欧拉，预报校正，龙格库塔的方法实现对x1微分=x2 x2微分=x3 x3微分=-800*x1-80*x2-24*x3+sin(t）； y=800x1 的运算-Numerical integration algorithm for the calculation of first-order differential equations: through the preparation of programming language, the use of Euler and forecast correction, Runge-Kutta method of achieving x1 differential = x2 x2 differential = x3 x3 differential =- 800* x1-80* x2-24* x3+ sin (t) y = 800x1 computing