社区发现算法GN算法

资源描述关于进程调度的操作系统实验的算法，可以点击来看看，进程调度的算法

此文件包含用于聚类分析的六个独立Fortran程序的完整代码

通过程序来表明bresenham算法画直线及中点画线法的原理。绘制网格，网格的交点为一个像素点，绘制bresenham算法画直线及中点画线法的像素点位置，在对应的像素点出打点。并且对对话框中输入的起点终点坐标判断是否在给定的范围内。

应用背景Massive multiuser MIMO (MISO): ◮ M ≫ K ≫ 1 (think 100 × 10 or 500 × 50) ◮ coherent, but simple, processing ◮ Potential to dramatically improve rate & reliability ◮ Potential to drastically scale down TX power ◮ Not only theory, at least one known testbed (64× ∼10) 关键技术 Massive MIMO Operation Not enough resources for pilots & CSI feedback, so operate in TDD. ◮ On the uplink, ◮ acquire CSI from uplink pilots and/or blindly from data ◮ detect symbols ◮ M ≫ K ⇒ linear processing (MRC, ZF, MMSE) nearly optimal ◮ On the downlink, ◮ use CSI obtained on the uplink ◮ make necessary adjustments based on reciprocity calibration ◮ apply multiuser MIMO precoding ◮ simple precoders desirable (and very good!): MRT, ZF, MMSE, ... ◮ MRC/MRT operation ◮ intracell interference will appear as

他们是源代码中的数字信号处理和数字通讯 （如 psk 和 bpsk 和 qam 和......

目标分配问题 应用遗传算法进行优化 使其对遗传算法的功能有一个较为全新的认识 适合初学者进行学习。

用VC实现从距离方位到经纬度的转换，已知一点A的经纬度和另一点B相对于点A的距离和方位，求点B的经纬度-With the VC to the latitude and longitude position from a distance conversion, known latitude and longitude point A, and another point A to point B relative to the distance and azimuth, latitude and longitude of point B

主成分分析算法，输入数据矩阵，得到投影变换主成分，用于数据降低维度。

这是我所有的家当哦,c语言源程序,其中有C语言二级考试的题目呢!-This is all my family"s, oh, c source language, which has two C-language examination questions!

最小二乘法一般是用来拟合直线和一些线性数据的，就是用一条直线来尽可能的表达若干的点的趋势，当然直线穿过所有的点是最好的，但往往有误差存在，所以拟合出的直线要求误差最小.设这些点为(x1,y1),(x2,y2)....(xn,yn).拟合直线为y=kx+b.-Ordinary least squares method is used to fit a straight line and a number of linear data, that is, as far as possible with a straight line to the point of the expression of a number of trends, of course, a straight line through all the points is the best, but often there is a margin of error, Therefore, a straight line fitting the requirements of the smallest error. established for these points (x1, y1), (x2, y2 )....( xn, yn). fitting straight line y = kx+ b.