求散乱点云法向算法

This is a program that will let you calculate roots with the Quadratic formula (including complex roots), Factorial of a number, Fibonacci series (and Pascals Triangle still under construction).

一个acm算法题目 问题描述： 有一个黑盒子，可视为一个15×10的二维矩阵，里面有一些空隙，在二维矩阵中用0表示空隙，用1表示被占有。现有一个仪器，可以从4个方向对盒子进行分行透视：从左到右，从左下到右上，从下到上，从右下到左上。透视可得到该二维矩阵的该行1的个数。要求，还原此矩阵。 输入：4行，每一行分别代表从左到右，从左下到右上，从下到上，从右下到左上透视所得的数据 输出：该矩阵 使用的方法是回溯法，具体见程序-a acm algorithm topic Problem description : a black box, as a 15 x 10 two-dimensional matrix, there are some gaps in two-dimensional matrix using 0 indicates the gap, with a show that occupies. An existing equipment, from the direction of four branches box for perspective : from left to right, from the lower left to upper right, from bottom to top, from the lower right to upper left. Perspective availability of the two-dimensional matrix of the line a number. Demand reduction of this matrix. Input : 4 firms on behalf of every line from left to right, from the lower left to upper right, from bottom to top, from the upper left to lower right perspective on data obtained from the output : the matrix method is the use of backtracking, see the specific procedures

贝叶斯算法(matlab编写) 安装,添加目录 /home/ai2/murphyk/matlab/FullBNT-Bayesian algorithm (Matlab preparation) installed, add directory/home/ai2/murphyk/matlab/FullBNT

最小二乘法拟和曲线，两个程序，大家-least squares fitting curves, the two procedures, we look at

松弛法默认松弛系数1.1到1.9-relaxation default relaxation factor from 1.1 to 1.9

如果一个字符串可以由某个长度为k的字符串重复多次得到，我们说该串以k为周期。例如，abcabcabcabc以3为周期（注意，它也可以6和12为周期,结果取最小周期3）。字符串的长度小于等于100，由调用者保证。详细描述：接口说明原型：int GetMinPeriod(char *inputstring);输入参数：char * inputstring：字符串返回值：

资源描述设集合R={r1,r2,...,rn}是要进行排列的n个元素，其中r1,r2,...,rn可能相同。 试着设计一个算法，列出R的所有不同排列。 即，给定n以及待排的n个可能重复的元素。计算输出n个元素的所有不同排列。

bit operation for 64.

只用几行代码就可以, 算出800位的圆周率, 很是神奇-only a few lines of code can calculate the circumference 800 rate is very magical

这是一个用梯形法求积的程序实例（VC）-This is a method for using trapezoidal plot examples of procedures (VC)