基于STM32的FFT和IFFT程序

它是关于一个命名集分区的源代码，是集分区问题中的一个acm

数据来源机器学习数据集，数据经过归一化处理，网络结构为7-7-3的网络。利用5折-交叉验证，做的三类分类代码，分类精度极高。

Conjugate gradient method for non-linear equations inC

本代码是《计算机常用数值计算算法与程序 C++版》一书的配套插值代码，这些C++程序已经在Virsual C++ 6.0环境下通过。注意，在VC++ 6.0中设置好路径，特别是include目录(文件夹)的路径，否则在编译时会出现找不到头文件的错误，使编译无法正常进行。-the code is "commonly used computer numerical algorithms and procedures C version," a book supporting interpolation code, these procedures have been in C C 6.0 Virsual environment through. The attention of the VC 6.0 installed path, in particular include directory (folder) path, otherwise there will be compiled header files could not find the mistakes and the compiler not normal.

用稀疏分解分析断齿的原因，经过验证在MATLAB中可以良好的运行从而进行分析，，

该程序用来解方程组的,非线性的和线性的,带有参数的方程组-The program group for the solution of equations, non-linear and linear equations with parameters

0 / 1背包问题是一个N P-复杂问题，为了解决该问题，，将用回溯算法解决该问题。既然想选择一个对象的子集，将它们装入背包，以便获得的收益最大，则解空间应组织成子集树的形状（如图1 6 - 2所示）。该回溯算法与4 . 2节的装载问题很类似。首先形成一个递归算法，去找到可获得的最大收益。然后，对该算法加以改进，形成代码。改进后的代码可找到获得最大收益时包含在背包中的对象的集合。-0/1 knapsack problem is a P-complex issues, in order to solve the problem, and will be used backtracking algorithm to solve the problem. As to the choice of a subset of object, they will load a backpack, in order to obtain the greatest profits, the solution should be organized into space subset of the shape of the tree (Figure 1 6-2 below). The backtracking algorithms and 4. Two loading problem is very similar. Forming a recursive algorithm to get the maximum benefit available. Then, this algorithm is modified to form code. Improved code can be found at the maximum benefits included in the backpack of a collection of objects.

Learnin Mathematics with the ABACUS Activity-book part4

基于msp430的温度检测，温度检测用的是ds18b20。里面配套的ad10原理图，pcb图，非常适合msp430初学者学习。

这个函数ObjectDetection Viola-Jones中检测的实现框架。在这个框架Haar-like特性用于快速目标检测。它支持训练分类器OpenCV的XML文件,可以在opencv.willowgarage.com上下载作为OpenCV的一部分软件