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参加数学建模的同学很可能会遇到这套题。本程序采用链表进行编写，很方便地解决了小白鼠问题。(Mathematical modeling of the students participating are likely to encounter this question, the program uses the list to solve the problem of mice, very convenient.)

二叉树的设计。包含二叉树结点类的设计以及二叉树的遍历。(Binary tree design. Contains the binary tree node class design, and Binary Tree Traversal.)

具有数据插入、修改、删除、显示、和查询功能的电话簿管理程序。 数据包括：人名、工作单位、电话号码、和E-mail地址。 可对记录中的姓名和电话号码进行修改。 可增加或删除记录。 可显示所有保存的记录。 可按人名或电话号码进行查询。 附加功能： 可修改单个记录的各项内容。 可重新建立电话簿。 可按人名或号码进行排序。 可统计名片数目及可再添加数目。 可插入单个名片并不破坏原有顺序(With the data to insert, modify, delete, display, and query functions of the phone book management program. The data include: the names, work units, phone number, and E-mail address. Can be modified to record the name and phone number. Increase or delete records. You can display all the records kept. According to the names or telephone number for queries. Additional features: you can modify the content of a single record. Can re-establish a Phonebook. According to the names or numbers to be sorted. Statistical card number and add the number. Insert a single card does not destroy the original order)

说明：  该程序实现二叉树的遍历功能，能够打印出二叉树的节点(The program realization of the binary tree traversal function, is capable of printing out the binary tree node)

序列二次规划算法，能求解包含约束和无约束的问题，非常方便。(Sequential quadratic programming algorithm to solve constrained and unconstrained contain the problem, very convenient.)

各种数据结构代码,欢迎下载,里面有JAVA,C,C++等等各种版本(Data structure and code, please download)

VC简易通讯录，加强C的编程，熟悉链表文件的使用等。(Simple VC contacts, strengthen C programming, familiar with the use of a linked list file.)

自己编写的几种经典的排序算法，里面有自己做的PPT详细讲解，希望有帮助吧(I have written several classic sorting algorithm, which own PPT explain in detail, I hope to help!)

输入迷宫行列数，1代表墙0代表路，之后系统生成路径(Enter the maze ranks number 1 represents 0 for Wall Road, after the system-generated path)

校园导游，可以选择景点序号来了解景点，通过选择两点可计算最短距离和最近路线。(Campus tour guide, you can choose the attractions serial number to understand the attractions of by selecting the shortest distance can be calculated and the recently routes.)