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二叉树的建立 中序遍历二叉树 把二叉树转换成双向链表(Binary tree in the establishment of traversing Binary conversion to binary tree into a doubly linked list)

.h文件。c++中的复数类，能够直接完成基本四则运算，输入输出流，完成一定范围内的比较运算(. H file. c++ classes in the plural, to directly perform basic arithmetic, input and output streams, to complete a range of comparison operators)

这个是数据结构课程设计中阿黄的CD的程序代码的工程文件包(This is a data structure curriculum design A yellow CD program code works package)

哈希表 数据结构课程设计 1.1问题描述 针对自己的班集体中的“人名”设计一个哈希表，使得平均查找长度不超过R，完成相应的建表和查表程序。 1.2基本要求 假设人名为中国姓名的汉语拼音形式。待填入哈希表的人名共有30个，取平均查找长度的上限为2。构造哈希函数，用链表法处理冲突。 1.3测试数据 读取熟悉的30个人的姓名作测试。(Hash table Data Structure Course Design 1.1 Description of the problem For their own class group of the "names" to design a hash table, making the average search length does not exceed R, the completion of construction of tables and look-up table corresponding procedures. 1.2 Basic requirements Assuming the name of the person called Chinese pinyin form. To be filled into a hash table names a total of 30, taking the average search length of the upper limit of 2. Construct a hash function, treatment with a list of conflict. 1.3 Test Data Read the familiar names of 30 individuals tested.)

程序可以实现哈弗曼自动编码功能！很详细的！很有参考价值！(Program can be Havermann automatic coding features! Very detailed! A good reference!)

迷宫算法，1代表可以通过，0代表墙壁，自动找寻路线(Maze algorithm, 1 can pass 0 for the walls, automatically find routes)

在VC中实现Bresenham算法画直线(Bresenham algorithm in VC draw a straight line)

说明：  用数据结构的遍历，对于小毛驴过河解决实际问题。(Traversing the data structure used for the small donkey across the river to solve practical problems.)

基于数据结构的图书管理系统，基本功能都有，可以拿来作为数据结构的课程设计(Based library management system data structures, basic function, can be used as a data structure of the curriculum design)

迷宫求解一般采用“穷举法”，逐一沿顺时针方向查找相邻块（一共四块－东(右)、南(下)，西(左)、北(上)）是否可通，即该相邻块既是通道块，且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)