登录
首页 » Visual C++ » a

a

于 2013-07-04 发布 文件大小:7067KB
0 296
下载积分: 1 下载次数: 1

代码说明:

说明:  进程死锁.资源分配图的绘制 建立所需数据结构;  使用题目21存成的资源分配图的文件作为输入;  编写资源分配图化简算法;  每化简一步,在屏幕上显示化简的当前结果;  最后给出结论,是否死锁,如思索给出死锁的进程及资源; (Process deadlock. Resource allocation mapping  establish the required data structures  Use title 21 deposit into resource allocation graph file as input  writing resource allocation map simplification algorithm  Each simplification step, on-screen display simplification of the current result  Finally, the conclusion of a deadlock, deadlock is given as thinking processes and resources )

文件列表:

进程死锁.资源分配图的绘制
.........................\12345.txt,73,2012-06-24
.........................\Debug
.........................\.....\.txt,74,2012-06-19
.........................\.....\LaodDlg.obj,13540,2011-06-17
.........................\.....\LaodDlg.sbr,0,2011-06-17
.........................\.....\MainFrm.obj,20486,2012-06-20
.........................\.....\MainFrm.pdb,25600,2012-06-19
.........................\.....\MainFrm.sbr,0,2012-06-20
.........................\.....\OsTest2.bsc,6218752,2012-06-24
.........................\.....\OsTest2.exe,168018,2012-06-24
.........................\.....\OsTest2.ilk,774368,2012-06-24
.........................\.....\OsTest2.obj,26760,2011-06-19
.........................\.....\OsTest2.pch,7131572,2011-06-07
.........................\.....\OsTest2.pdb,754688,2012-06-24
.........................\.....\OsTest2.res,7344,2012-06-20
.........................\.....\OsTest2.sbr,0,2011-06-19
.........................\.....\OsTest2.suo,3072,2011-06-04
.........................\.....\OsTest2Doc.obj,14696,2011-06-07
.........................\.....\OsTest2Doc.sbr,0,2011-06-07
.........................\.....\OsTest2View.obj,187953,2012-06-24
.........................\.....\OsTest2View.sbr,0,2012-06-24
.........................\.....\ResourceDlg.obj,11695,2012-06-20
.........................\.....\ResourceDlg.sbr,0,2012-06-20
.........................\.....\SaveDlg.obj,13980,2011-06-17
.........................\.....\SaveDlg.sbr,0,2011-06-17
.........................\.....\SelectDlg.obj,20346,2012-06-20
.........................\.....\SelectDlg.sbr,0,2012-06-20
.........................\.....\StdAfx.obj,105568,2011-06-07
.........................\.....\StdAfx.sbr,1374950,2011-06-07
.........................\.....\Test1.exe,553019,2011-06-05
.........................\.....\Test1.ilk,799160,2011-06-05
.........................\.....\Test1.pch,2247428,2012-06-19
.........................\.....\Test1.pdb,1131520,2011-06-05
.........................\.....\vc60.idb,361472,2012-06-25
.........................\.....\vc60.pdb,561152,2012-06-24
.........................\LaodDlg.cpp,1031,2011-06-17
.........................\LaodDlg.h,1177,2011-06-17
.........................\MainFrm.cpp,2926,2012-06-20
.........................\MainFrm.dsp,3413,2012-06-19
.........................\MainFrm.dsw,522,2012-06-19
.........................\MainFrm.h,1543,2011-06-14
.........................\MainFrm.ncb,33792,2012-06-19
.........................\MainFrm.opt,48640,2012-06-19
.........................\MainFrm.plg,920,2012-06-19
.........................\OsTest2.aps,29804,2012-06-24
.........................\OsTest2.clw,3982,2012-06-25
.........................\OsTest2.cpp,4423,2011-06-16
.........................\OsTest2.dsp,5025,2011-06-15
.........................\OsTest2.dsw,522,2011-06-03
.........................\OsTest2.h,1371,2011-06-05
.........................\OsTest2.ncb,140288,2012-06-25
.........................\OsTest2.opt,53760,2012-06-25
.........................\OsTest2.plg,248,2012-06-25
.........................\OsTest2.rc,13495,2012-06-20
.........................\OsTest2Doc.cpp,1762,2011-06-03
.........................\OsTest2Doc.h,1486,2011-06-03
.........................\OsTest2View.cpp,21161,2012-06-24
.........................\OsTest2View.h,2656,2011-06-19
.........................\ReadMe.txt,4019,2011-06-03
.........................\res

.........................\...\OsTest2.rc2,399,2011-06-03

.........................\resource.h,1328,2011-06-15
.........................\ResourceDlg.cpp,1745,2012-06-20
.........................\ResourceDlg.h,1254,2012-06-20
.........................\SaveDlg.cpp,1060,2011-06-17
.........................\SaveDlg.h,1198,2011-06-17
.........................\SelectDlg.cpp,2745,2012-06-20
.........................\SelectDlg.h,1491,2011-06-16
.........................\StdAfx.cpp,209,2011-06-03
.........................\StdAfx.h,1054,2011-06-03

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • lvxingshang
    一个经典的旅行商问题源码,不是最优解,只是一种 思路(A classic traveling salesman problem source is not the optimal solution, just a thought)
    2012-11-09 01:33:02下载
    积分:1
  • 1
    可以实现判断二叉树是否为完全二叉树、判断两棵二叉树是否镜像对称、求一棵二叉树的一个最长枝等功能(Can determine whether the binary tree is complete binary tree to determine whether two binary mirror symmetry, one of the longest seeking a binary tree branches and other functions)
    2013-11-13 21:16:53下载
    积分:1
  • list-and-array
    数组的定义与使用,数组的运算,字符串的输入与输出,冒泡排序(list and array)
    2013-10-17 11:32:30下载
    积分:1
  • bfs
    这是BFS算法的实现。用C语言实现的。好好学习吧。(This is achieved BFS algorithm. Implemented using C language. Learn it.)
    2013-12-05 15:56:50下载
    积分:1
  • 0908030206xin
    一、 地理数据文件应用 对由点、线、面构成的地理数据文件进行打开、读取、关闭操作。 要求: 1、在C++环境下,通过程序设计实现文本格式数据文件的操作; 2、在打开数据文件后,生成点、线、面三个链表,分别用于记录三种类型的数据。 3、数据文件结构说明 (Geographic data file applications by point, line, surface consisting of geographic data file open, read, and close operations. Requirements: in C++ environment, through the program design text format data file operations 2, open the data file, generate points, lines, surfaces three linked list, respectively, for the record three types of data. 3, a data file structure)
    2012-09-14 20:33:26下载
    积分:1
  • Huffman
    数据结构,利用霍夫曼树实现文本数据的压缩。(Huffman data compression and decompression.)
    2014-01-28 18:25:24下载
    积分:1
  • 最短路径c++语言
    说明:  用从c++写的floyd最短路径算法,可以求邻接矩阵任意两点的最短路径。(from using c++ to write the Floyd shortest path algorithm, can help adjacency matrix arbitrary 2:00 Shortest Path.)
    2020-09-20 14:07:55下载
    积分:1
  • backtrackng
    给定n种物品和一背包。物品i的重量是wi>0,价值为vi>0,背包的容量为c。选择装入背包的物品,使得装入背包中物品的总价值最大。(Given n kinds of goods and a backpack. Weight of the item i is wi> 0, the value of vi> 0, knapsack capacity c. Select the items into the backpack, so into the backpack of items in the total value of the maximum.)
    2017-01-01 17:51:23下载
    积分:1
  • Sort
    排序程序,包含快速排序、归并排序、谢尔排序、插入排序。输出了比较次数和移动次数。(It is a sort program, including quick sort, merge sort, shell sort and insert sort.It outputs the compare times and movement times.)
    2009-05-24 18:53:10下载
    积分:1
  • stack
    数据结构 堆栈 实现了以下功能: cout<<"----------------主菜单---------------"<<endl <<"* 1.建立 *"<<endl <<"* 2.输出 *"<<endl <<"* 3.判断栈是否为空 *"<<endl <<"* 4.栈的长度 *"<<endl <<"* 5.输出栈顶元素 *"<<endl <<"* 6.进栈 *"<<endl <<"* 7.出栈 *"<<endl <<"* 8.遍历 *"<<endl <<"* 9.数制转换 *"<<endl <<"* 10.清空 *"<<endl <<"* 11.销毁 *"<<endl <<"* 12.退出 *"<<endl <<"--------------------------------------"<<endl<<endl (data structure stack)
    2013-11-01 11:05:10下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载