huffman_src22

魔方问题 数据结构 使用c++ 经典问题(Cube problem Data Structure Using c++ Classic problem)

POJ141的源代码，以空间换时间，速度很快很好用。(POJ141 the source code for time in space, fast easy to use.)

假设要在足够多的会场里安排一批活动，并希望使用尽可能少的会场。设计一个有效的贪心算法进行安排。（这个问题实际上是著名的图着色问题。若将每一个活动作为图的一个顶点，不相容活动间用边相连。使相邻顶点着有不同颜色的最小着色数，相应于要找的最小会场数。） 对于给定的k 个待安排的活动，编程计算使用最少会场的时间表。 (Suppose you want to arrange a number of activities in the hall more than enough, and want to use as little as possible venue. Design an effective greedy algorithm arrangements. (This problem is actually well-known graph coloring problem. If each activity as a vertex map, with the side connected between incompatible activities. Makes coloring adjacent vertices with minimum number of different colors, corresponding to looking The minimum number of venue.) K to be arranged for a given activity, calculated using a minimum of venue programming schedule.)

数据结构与算法分析的 C++检索代码，很经典(the code of Data structure)

最小生成树算法 克鲁斯法尔算法 球最佳路径(kulru method class maiun void cx )

校园导航系统包含佛山科技学院本部校区的校园景点平面图。通过系统的各功能不仅可以查询任意景点的编号，名称，简介等信息，还可以查询任意两景点间的最短路径及长度和所有路径及长度。另外，还可以通过一系列操作增加，更改或删除任意的景点的各信息。(Contains the campus attractions plan of the campus Foshan Institute of Technology campus navigation system. Through the function of the system not only can query any spots number, name, profile and other information, can also query the shortest path and arbitrary length between two spots and all paths and the length of. In addition, can also increase through a series of operations, the information change or delete any of the attractions.)

计算点到直线的距离．输入两点坐标确定一个直线，再输入一个点的坐标，计算该点到直线的距离．(Calculated point to the straight line distance. Enter the coordinates of two points determine a straight line, and then input the coordinates of a point, to calculate the straight-line distance between points.)

一个经典的旅行商问题源码，不是最优解，只是一种 思路(A classic traveling salesman problem source is not the optimal solution, just a thought)

说明：  nuaa1108 多少连续的1 解题报告(Problem solving report )

遗传算法实现飞机在三维空间的航迹规划 C代码(Genetic Algorithm Route Planning C code)