005

改进爬山算法，用于风力发电机实现风能最大追踪，找到最佳叶尖速比，实现最大功率(modified hill-climbing algorithm for wind turbine with MPPT)

Monkeys and peach,Monkeys and peach(Monkeys and peach)

使用三叉链表实现的哈夫曼树,统计inputfile1.txt中各字符的出现频率，并据此构造Huffman树，编制Huffman 码；根据已经得到的编码，对01形式的编码段进行译码。 具体的要求： 1．将给定字符文件编码，生成编码，输出每个字符出现的次数和编码； 2．将给定编码文件译码，生成字符，输出编码及其对应字符。 (Emergence of the frequency of each character in the trigeminal lists using the Huffman tree, statistics inputfile1.txt, and accordingly the Huffman tree structure, preparation of Huffman code according to the coding has been. 01 to form the code segment for decoding. Specific requirements: 1 coding the given character file, generating the encoding, and outputting the number and encoding of each character 2 will be given the encoding file decoding, generating the character, the output code and its corresponding character.)

根据所选定的字符顺序，按照从大到小的规则，对字符进行插入排序，(Insert and sort characters)

参加运动会的 个学校编号为 。比赛分成 个男子项目和 个女子项目，项目编号分别为 和 。由于各项目参加人数差别较大，有些项目取前五名，得分顺序为7，5，3，2，1；还有些项目只取前三名，得分顺序为5，3，2。写一个统计程序产生各种成绩单和得分报表。 2、要求产生各学校的成绩单，内容包括各校所取得的每项成绩的项目号、名次（成绩）、姓名和得分；产生团体总分报表，内容包括校号、男子团体总分、女子团体总分和团体总分。 3、测试数据：对于 ， ， ，编号为奇数的项目取前五名，编号为偶数的项目取前三名，设计一组实例数据。 (The school serial number participating in Games is. Competition divides into men s event and women s event , the project serial number parts for the sum. The difference is bigger since every project participates in a number , some projects choose the first five , score order is 7 , 5 , 3 , 2 , 1 Still have some of projects taking the first three places , score only being 5 , 3 , 2 in proper order. Write a form for report counting procedure producing the various school report card and score. 2, demands the school report card producing every school , content includes every achievement project number , position in a name list (achievement) , full name and score per got by school Produce the group total points form for report , content including the school number , male person group total points , woman group total points and group total points. 3, testing data: Be that the odd number project chooses the first five to the serial number, the serial number is that the even number project c)

数据结构中基于约瑟夫环问题，用C++方式实现的。。。。。(Data structure based on Josephus problem with C++ a manner. . . . .)

二查树遍历文件，可以用于程序测试，有喜欢的朋友要多多使用哦(Two check tree traversal file that can be used for program testing)

吴伟民版数据结构每个算法的c实现方法，并模块化处理，将各个功能分开编程，有助于移植使用(failed to translate)

求二叉树的深度: 给定一个有根二叉树，规定连接两个节点的每条边长度是1，定义树的深度为根到叶子节点距离的最大值。 (Description 给定一个有根二叉树，规定连接两个节点的每条边长度是1，定义树的深度为根到叶子节点距离的最大值。 )

输入迷宫行列数，1代表墙0代表路，之后系统生成路径(Enter the maze ranks number 1 represents 0 for Wall Road, after the system-generated path)