jiaotongzixun

算法导论的英文版，讲解算法的非常经典的书。(English version of Introduction to Algorithm. A classical book to teach algorithm.)

这是数据结构很重要的程序，主要是课后题的答案，和代码，功能很强大(the data struct of the book)

some problems about c++.(car.cpp)

链表的建立及相关处理，包括排序，删除，初始化，增加，删除等等，且程序已运行通过。(The establishment of a linked list and related processing, including sorting, delete, initialization, increase, delete, etc., and the program has been run through )

最短路径算法。 用无向带全图的邻接矩阵存储图，确定从源点出发到其它各点的最短路径。 输入：图中包含的顶点数n 边数m， 各边权值，用邻接矩阵或者邻接表存储。 输出：源点到其它各点的最短路径值。(Shortest path algorithm. Adjacency matrix storage with undirected graph with a full figure, determine the starting point of the shortest path from the source point of each other. Input: Vertices figure included n the number of edges m, the weight of each side, with the adjacency matrix or adjacency table storage. Output: source shortest path to value each other points.)

这是birch C语言的源代码。里面有详细的代码注释方便学习birch算法(birch c)

使用C语言建立带头结点链表实现了集合。并进行了性能上的优化。(Achieve set using C to build list witch head node. And make optimization in performance.)

二叉排序树的建立、插入与删除。按递增顺序插入N个整数，并按同样顺序删除；(Binary sort tree establishment, insertions and deletions. Insert N integers in ascending order, press the same sequence deleted )

一道poj上的问题的解答，棋盘上的距离问题。即实现棋盘上从一个点移动到王，后，兵之间最短步数的解答。(A poj answers to your questions on the chessboard distance problem. That is, move from one point to the king on the board, after the shortest number of steps between the soldiers answer.)

任务：实现Dijkstra算法 工程名：Project_ShortestPath 要求：实现Dijkstra算法，算法主体写在CGraph类中；要求是从command窗口中输入源节点编号，并在command窗口中输出从源节点到所有目的节点的最短路长及最短路。注：要输出整条路径，而不仅仅是前一跳，也不允许逆序输出。 (Task: Dijkstra' s algorithm to achieve the project name: Project_ShortestPath requirements: achieve Dijkstra algorithm, the algorithm written in the body CGraph class requires input from the command window, the source node number, and in the command window, all of the output from the source node to the destination node shortest long and the shortest. Note: To export the entire path, not just before the jump, do not allow reverse output.)