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jose
约瑟夫环(约瑟夫问题)是一个数学的应用问题:已知n个人(以编号1,2,3...n分别表示)围坐在一张圆桌周围。从编号为k的人开始报数,数到m的那个人出列;他的下一个人又从1开始报数,数到m的那个人又出列;依此规律重复下去,直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1,最后结果+1即为原问题的解。
(Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)
- 2015-01-09 17:28:41下载
- 积分:1
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Dijkstra
迪杰斯特拉算法,数据结构,C语言写的,上大学计算机系会用到的。。。(Dijkstra algorithm, data structures, C language written on the Department of Computer Science will be used. . .)
- 2013-03-06 21:50:34下载
- 积分:1
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Fa_Pai
关于随机发牌算法的小程序,作为数据结构的大作业,开发环境是VC(Random licensing algorithm for small procedures, as big job data structures, the development environment is VC)
- 2014-10-16 17:54:20下载
- 积分:1
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class
给定m个n维向量a , a , ,am 1 2 ,向量分类问题要求将相同的向量划分为同一类。试用
抽象数据类型表设计解向量分类问题的有效算法。(Given m a n-dimensional vector a, a,, am 1 2 )
- 2008-05-05 22:03:41下载
- 积分:1
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ds3
单向链表的创建与操作
设单向链表中节点的数据域的数据类型为整型,编写函数实现以下操作:
(1)实现单向链表的创建(包括初始化)与输出操作,节点的个数及节点的数据由用户输入。
(源代码:ds3-1.c)
(2)查找给定的单链表中的第i个节点,并将其地址返回。若不存在第i个节点,则返回空地址。
(源代码:ds3-2.c)
(3)查找给定的单链表中值为n的节点,并将其地址返回。若不存在值为n的节点,则返回空地址。同时,还应通过参数传回该节点的序号。
(源代码:ds3-3.c)
(4)删除给定的单链表中的第i个节点,成功返回1,失败返回0。
(源代码:ds3-4.c)
(5)删除给定的单链表中值为n的节点,成功返回1,失败返回0。
(源代码:ds3-5.c)
(6)在给定的单链表的第i位上插入值为n的节点。
(源代码:ds3-6.c)
(7)在给定单链表的值为m的节点的前面插入一个值为n的节点。
(源代码:ds3-7.c)
(Creation and operation of a one-way linked list
Set up a one-way linked list data type node integer data fields , write a function to achieve the following:
( 1 ) achieve the creation of a one-way linked list ( including initialization ) and output operation , the number of nodes and node data entered by the user .
( Source : ds3-1.c)
( 2 ) Find a single list given in the i-th node and returns its address . Without the presence of the i-th node , returns an empty address.
( Source : ds3-2.c)
( 3 ) Find a given node in a given value of n single list , and return address . Without the presence of the value of n nodes , returns an empty address. Meanwhile, the number should be returned by the parameters of the node .
( Source : ds3-3.c)
( 4 ) Delete the given singly linked list in the i-th node , the successful return 1, else return 0 .
( Source : ds3-4.c)
( 5 ) to delete a single node in the list is given n , the successful return 1, else return 0 .
( Source : ds3-5.c)
( 6 ) )
- 2014-05-11 19:19:41下载
- 积分:1
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optional-project-blackjact
经典数据结构作业,黑杰克游戏。要求程序可以连续打10次,每场比赛的赢家,赢得一个点(两点一倍)。在结束的10场比赛为你和电脑打印出的总奖金。(Write a program that simulates a simplified version of the game "BlackJack". A deck of cards numbered 2 to 10, jacks, queens, kings, and aces is used, where jacks, queens and kings are counted as 10s, and aces are either 1 or 11 at your choice. )
- 2012-12-08 11:46:33下载
- 积分:1
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2_24to2_28
双向链表 清华大学 出版社 《数据结构 C++》 源代码实现(Tsinghua University Press doubly linked list <data structure, C++> source code)
- 2011-02-05 22:08:53下载
- 积分:1
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BigNumeberOperator
这是高精度大数运算的源码,对于大于64位的整形数字的四则运算,是万能的啊……(This is the code of big number s operator.)
- 2011-08-09 15:25:09下载
- 积分:1
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calculation
数据结构计算算术表达式算法,可以计算小数点及较复杂的运算表达式(Data structure algorithms calculate arithmetic expression, we can calculate the decimal point and more complex operations expression)
- 2010-12-24 13:11:25下载
- 积分:1
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FIFO-c
说明: 操作系统先来先服务调度算法模拟(C描述)(Operating a first-come first-served scheduling simulation (C description))
- 2010-04-13 00:02:35下载
- 积分:1