BiTree

迷宫求解一般采用“穷举法”，逐一沿顺时针方向查找相邻块（一共四块－东(右)、南(下)，西(左)、北(上)）是否可通，即该相邻块既是通道块，且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)

数据结构与算法分析的 C++检索代码，很经典(the code of Data structure)

最优二叉搜索树问题具有最优子结构性质，即其任意一棵子树都是一棵独立的最优二叉搜索树，所以可以采用动态规划方法，并且在每次更新时保存子树的根。(Optimal binary search tree problem has optimal substructure property that any of its sub-tree are an independent optimal binary search tree, so you can use dynamic programming methods, and save each update subtree roots.)

参加运动会的 个学校编号为 。比赛分成 个男子项目和 个女子项目，项目编号分别为 和 。由于各项目参加人数差别较大，有些项目取前五名，得分顺序为7，5，3，2，1；还有些项目只取前三名，得分顺序为5，3，2。写一个统计程序产生各种成绩单和得分报表。 2、要求产生各学校的成绩单，内容包括各校所取得的每项成绩的项目号、名次（成绩）、姓名和得分；产生团体总分报表，内容包括校号、男子团体总分、女子团体总分和团体总分。 3、测试数据：对于 ， ， ，编号为奇数的项目取前五名，编号为偶数的项目取前三名，设计一组实例数据。 (The school serial number participating in Games is. Competition divides into men s event and women s event , the project serial number parts for the sum. The difference is bigger since every project participates in a number , some projects choose the first five , score order is 7 , 5 , 3 , 2 , 1 Still have some of projects taking the first three places , score only being 5 , 3 , 2 in proper order. Write a form for report counting procedure producing the various school report card and score. 2, demands the school report card producing every school , content includes every achievement project number , position in a name list (achievement) , full name and score per got by school Produce the group total points form for report , content including the school number , male person group total points , woman group total points and group total points. 3, testing data: Be that the odd number project chooses the first five to the serial number, the serial number is that the even number project c)

设有一头指针为L的带有表头结点的非循环双向链表，其每个结点中除有prev（前驱指针），data（数据）和next（后继指针）域外，还有一个访问频度域freq。在链表被起用前，其值均初始化为零。每当在链表中进行一次Locate(L,x)运算时，令元素值为x的结点中freq域的值增1，并使此链表中结点保持按访问频度非增（递减）的顺序排列，同时最近访问的结点排在频度相同的结点的最后，以便使频繁访问的结点总是靠近表头。试编写符合上述要求的Locate(L,x)运算的算法，该运算为函数过程，返回找到结点的地址，类型为指针型。(Has a head pointer is non-circular doubly linked list L with a header node, each node in addition to prev (precursor pointer), data (data) and next (successor pointers) outside, there is an access frequency degree domain freq. Before the list was hired, their values are initialized to zero. Whenever carried out in the list once Locate (L, x) when the operation, so that the element node x is the value in freq domain by one, and keep this list in the node-access frequency of non-increasing (decreasing) the order, while a recent visit to the nodes in the same row of the frequency of the last node, so that the nodes are frequently accessed tables are always near the head. Locate (L, x) algorithm is prepared in accordance with the above requirements of the test operation, the operation as a function of the process, return to find the address of the node of type pointer.)

使用的排序算法，非常不错的思维，比较其他有较大优势(Sorting algorithm used, very good ideas, have greater advantages compared with other)

数据结构课程设计 数据结构B+树 B+ tree Library(B+ tree Library)

主要是DIJKSTRA经典算法，可以作为单个算法来读，也可以调用。(DIJKSTRA mainly classical algorithm can be read as a single algorithm can also be called.)

一道poj上的问题的解答，棋盘上的距离问题。即实现棋盘上从一个点移动到王，后，兵之间最短步数的解答。(A poj answers to your questions on the chessboard distance problem. That is, move from one point to the king on the board, after the shortest number of steps between the soldiers answer.)

这个是关于数据结构中冒泡排序算法的实现，大家可以利用这个为基础，进一步研究和利用排序(This is a data structure on the Bubble Sort algorithm, we can use this as a basis for further study and use of sorting)