data-structure-paper

校园导游，可以选择景点序号来了解景点，通过选择两点可计算最短距离和最近路线。(Campus tour guide, you can choose the attractions serial number to understand the attractions of by selecting the shortest distance can be calculated and the recently routes.)

说明：  进程死锁.资源分配图的绘制 建立所需数据结构；  使用题目21存成的资源分配图的文件作为输入；  编写资源分配图化简算法；  每化简一步，在屏幕上显示化简的当前结果；  最后给出结论，是否死锁，如思索给出死锁的进程及资源； (Process deadlock. Resource allocation mapping  establish the required data structures  Use title 21 deposit into resource allocation graph file as input  writing resource allocation map simplification algorithm  Each simplification step, on-screen display simplification of the current result  Finally, the conclusion of a deadlock, deadlock is given as thinking processes and resources )

用c++实现的haffman tree 小程序，仅供参考 。 (The the haffman tree applet realized with c++ for reference only.)

VC++常用的数据结构类源码 这是我在VC++日常开发中收集的一些经常用到的类库，每一款都可以轻松重用，这些类库适用于vs2003及以上的开发环境，其中 Thread 和 Delegate 是从C#中得到的灵感，还有一些是在使用开源代码或其它语言时得到的启发和灵感。个人认为部分代码还算好用，所以拿来分享一下。部分类库附带有例子，欢迎参考。 (Commonly used data structures in VC++ class source This is the daily development of VC++ I collected some frequently used library, each designed to easily reuse these libraries apply to vs2003 and development environment, including Thread and Delegate inspiration from C#, there are some inspired use of open source code or other languages ​ ​ and inspiration. Personally think that part of the code is fairly easy to use, so used to share. Some class library included with examples for reference.)

使用不同的方法解决背包问题：本算法采用的是动态规划方法，比较好的解决背包问题。(Use different methods to solve knapsack problem: The algorithm is a dynamic programming approach, a better solution to knapsack problem.)

数据结构 二叉树的操作，可以对二叉树进行最基本的操作，先建立二叉树。(The operation of the binary tree, binary tree with the most basic operation, first create a binary tree.)

表达式cpp实现 数据结构实验源代码 实现前序、中序、后序表达式(Expression codes Formerorder expressions regular expression&Postorder expressions )

算法导论的英文版，讲解算法的非常经典的书。(English version of Introduction to Algorithm. A classical book to teach algorithm.)

迷宫求解一般采用“穷举法”，逐一沿顺时针方向查找相邻块（一共四块－东(右)、南(下)，西(左)、北(上)）是否可通，即该相邻块既是通道块，且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)

实现对二叉树的操作：建树、遍历、求层高、叶子数和结点数等(binary tree)