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binary-search
此代码为折半查找算法,适用于有序表,欢迎各位下载(This code is the binary search algorithm for ordered lists
)
- 2011-07-06 15:50:17下载
- 积分:1
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Cpp1
校园导游,可以选择景点序号来了解景点,通过选择两点可计算最短距离和最近路线。(Campus tour guide, you can choose the attractions serial number to understand the attractions of by selecting the shortest distance can be calculated and the recently routes.)
- 2012-06-20 21:57:32下载
- 积分:1
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3_abstract_data_struct
数据结构:抽象数据类型的介绍;讲述如何构造函数和如何实现;(Data structure: the introduction of abstract data types on how to structure function and how to achieve )
- 2008-04-14 22:56:33下载
- 积分:1
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约瑟夫环的循环链表实现
约瑟夫环的循环链表实现,这个程序比较完整,有需要做试验的请速速下载。(Josephus cycle Chain achieved, the procedure is complete, the pilot needs to be done urgently requested to download.)
- 2005-07-03 19:38:38下载
- 积分:1
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ALGraph
学数据结构自己总结的东西,希望对大家有所帮助。(Learn data structure sum things up, we want to help.)
- 2013-03-08 19:50:18下载
- 积分:1
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adms
阿当姆斯显式和隐式求解方法,用四阶龙格库塔作为起始,然后运用四阶阿当姆斯算法求解初值问题。主要程序包含在test2.cpp中,方法简单易懂。编译环境VC2010(Adam James explicit and implicit method for solving fourth-order Runge-Kutta as a start, then use the fourth-order A Williams algorithm for solving initial value problem. The main program contains in test2.cpp method is simple and easy to understand. Compile environment VC2010)
- 2012-06-09 11:27:18下载
- 积分:1
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ds3
单向链表的创建与操作
设单向链表中节点的数据域的数据类型为整型,编写函数实现以下操作:
(1)实现单向链表的创建(包括初始化)与输出操作,节点的个数及节点的数据由用户输入。
(源代码:ds3-1.c)
(2)查找给定的单链表中的第i个节点,并将其地址返回。若不存在第i个节点,则返回空地址。
(源代码:ds3-2.c)
(3)查找给定的单链表中值为n的节点,并将其地址返回。若不存在值为n的节点,则返回空地址。同时,还应通过参数传回该节点的序号。
(源代码:ds3-3.c)
(4)删除给定的单链表中的第i个节点,成功返回1,失败返回0。
(源代码:ds3-4.c)
(5)删除给定的单链表中值为n的节点,成功返回1,失败返回0。
(源代码:ds3-5.c)
(6)在给定的单链表的第i位上插入值为n的节点。
(源代码:ds3-6.c)
(7)在给定单链表的值为m的节点的前面插入一个值为n的节点。
(源代码:ds3-7.c)
(Creation and operation of a one-way linked list
Set up a one-way linked list data type node integer data fields , write a function to achieve the following:
( 1 ) achieve the creation of a one-way linked list ( including initialization ) and output operation , the number of nodes and node data entered by the user .
( Source : ds3-1.c)
( 2 ) Find a single list given in the i-th node and returns its address . Without the presence of the i-th node , returns an empty address.
( Source : ds3-2.c)
( 3 ) Find a given node in a given value of n single list , and return address . Without the presence of the value of n nodes , returns an empty address. Meanwhile, the number should be returned by the parameters of the node .
( Source : ds3-3.c)
( 4 ) Delete the given singly linked list in the i-th node , the successful return 1, else return 0 .
( Source : ds3-4.c)
( 5 ) to delete a single node in the list is given n , the successful return 1, else return 0 .
( Source : ds3-5.c)
( 6 ) )
- 2014-05-11 19:19:41下载
- 积分:1
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a
说明: 100米比赛排名 C++实现100米比赛排名 C++实现(100m rankings C++, the 100 meters ranks C++,)
- 2010-11-19 23:24:18下载
- 积分:1
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permutations
组合数学全排列,包含有六种全排列的方法,字典序法(math of permutations)
- 2011-12-12 10:51:16下载
- 积分:1
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yuesefu
数据结构经典算法 约瑟夫问题 c++ 已经测试通过(josephus c++)
- 2012-12-02 16:23:02下载
- 积分:1