登录
首页 » Visual C++ » maze

maze

于 2013-12-13 发布 文件大小:1081KB
0 230
下载积分: 1 下载次数: 4

代码说明:

  迷宫求解一般采用“穷举法”,逐一沿顺时针方向查找相邻块(一共四块-东(右)、南(下),西(左)、北(上))是否可通,即该相邻块既是通道块,且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • xiao-yuan-dao-you
    说明:  设计济南大学校园平面图,所含的景点不少于10个。以图中顶点表示校内各景点,存放景点名称、代号、简介等信息;以边表示路径,存放路径长度等相关信息。 为来访客人提供图中任意景点相关信息的查询。 为来访客人提供图中任意景点的问路查询,即查询任意两个景点之间的一条最短的简单路径。 选作内容: 求校园的关节点。 提供图中任意景点查询,即求任意两点间的所有路径。 校园导游图的景点和道路的修改扩充功能。 扩充道路信息,如道路类别,沿途景色等级,一直可按客人所需分别查询人行路径或车行路径或观景路径。(Design jinan university campus plan, contains at least 10 spots in each vertex said in scenic spots, deposit attractions at the information such as the code name introduction On the path, deposit path length said related information )
    2011-03-21 19:54:06下载
    积分:1
  • BDX
    设计、编写和调试面向对象C++程序,实现任意两个同类数据比大小 的通用函数(模板),涵盖普通数值型数据之间的比较、两个字符串之间的比较 (按字典序)、两个复数之间的比较(按模大小)等,并通过主函数加以调用和 测试。(Design, writing and debugging of object-oriented C++ procedures to achieve similar data than the size of any two generic functions (template), covering general comparison between numerical data, the comparison between the two strings (lexicographically), two Comparison between complex numbers (modulo the size), and through the main function to be invoked and tested.)
    2020-11-28 13:49:29下载
    积分:1
  • Task1-trial--10211281--zly
    描述:足球俱乐部包括球员、普通行政人员。球员有姓名、年龄、能力、年薪、转会费、进球总数、服役年限等重要参数;普通行政人员有姓名、年龄、能力、年薪等参数。你需要给相关管理机构开发一个管理程序,实现对众多足球俱乐部管理的基本功能。具体功能包括: a) 俱乐部的增删改查,俱乐部的属性包括名称、现金、其下人员; b) 可以对所有球员的各项属性进行简单搜索,支持输入多个条件,条件之间用&&连接,例如: i. “年龄不大于25且服役年限大于5年且进球数大于100的球员”,查询表达式:!(@age>25) && @experience>5 && @kick>100 c) 支持球员在不同俱乐部间的买卖,买卖需符合以下条件:作为买方的俱乐部的现金>=球员的转会费,交易完成后,卖方将得到转会费。 要求: d) 必须采用面向对象的方式,使用类组织数据结构,并注意类的继承关系; e) 在题目要求基础上可以自行扩展功能,提供扩实用扩展功能者适当加分(加分不超过5分)。 (Description: Football club including players, general administrative staff. Player name, age, ability, salary, transfer fee, total number of goals, service life and other important parameters ordinary administrative staff name, age, ability, salary and other parameters. You need to give the relevant management agencies to develop a management program to achieve the number of football club management s basic functions. Specific features include: a) the club CRUD, the name of the club s property, including cash, under which personnel b) all players can perform a simple search of the property, supports input multiple conditions with && connection between conditions, for example: i. "Age is not greater than 25 and greater than 5 years service life and goals more than 100 players," query expression:! (@ age> 25) && @ experience> 5 && @ kick> 100 c) Support the players traded between different clubs, the sale subject to the following conditions: As a buyer s club cash> = pl)
    2013-08-20 10:09:29下载
    积分:1
  • sstring
    利用串来比较数据大小,代码中有两个串,通过串来比较大小( 10/5000 Use the string to compare the data size)
    2016-12-20 17:05:29下载
    积分:1
  • BinarySortTree
    二叉排序树,可以实现插入,删除,查找,创建功能(Binary sort tree,you can achieve the insert,delete,search,create functional)
    2009-12-03 10:53:04下载
    积分:1
  • test
    矩阵运算器,c语言编程,数据结构,免费下载(Matrix calculator, c language programming, data structures, free download)
    2008-05-04 09:32:59下载
    积分:1
  • data-struct
    对于数据结构每一章节的相应的练习题,巩固好数据结构(To consolidate data structure corresponding practice questions for each chapter of the data structure)
    2012-10-09 17:03:41下载
    积分:1
  • Lecture6
    数据结构中链式队列和堆栈的循环用法,非常有用(Queue data structure in the chain and the cycle stack usage, very useful)
    2011-07-27 15:30:29下载
    积分:1
  • 00
    说明:  还是通讯录系统 增删改查 课程设计 本科学校要求的数据结构课程设计(Or address book CRUD the data structures required by the curriculum design undergraduate schools curriculum design)
    2012-06-17 21:36:24下载
    积分:1
  • Prim
    编程实现Prim算法,基于最小堆数据结构,生成最小代价生成树。 (其中随机生成点和边,形成连通图) 根据输入的顶点数的不同,分析时间复杂度。(Implement Prim’s algorithms based on min-heap and disjoint set data structure for constructing a minimum cost spanning tree. Generate weighted undirected complete graph for given size n according to the following approach: 1) Randomly generate n points ( ) on a plane 2) Randomly generate k pairs of points as edges of the graph. 3) The weight of an edge of the graph is defined as the the Euclidean distance between two endpoints of the edge. )
    2011-06-11 16:28:53下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载