DIJKSTRA算法实现的最短路径程序linjiebiaoshortpath

约瑟夫问题，用数据结构的循环链表实现约瑟夫问题的解答(Joseph problems，30 people in a circle, and inspires us with a circular chain to said. Can use structure array to make a cycle chain. The structure has two members, one for pointing down a pointer to a circular chain )

堆栈实现C++,以VC++环境为准——逍遥大洋至上(The stack of the C++, VC++ environment will prevail)

mfc 连接数据库 用mfc做的管理系统，戏中包括数据库连接(mfc connect to the database)

数据结构中图的遍历Data structure traversal of center(Data structure traversal of center)

This is a C++ code. It finds out if the tree is a binary search tree (BST)or not, where the BST is one of data structures types.

经典的 数据结构问题 八皇后问题。问题是在8*8的棋盘上放置棋子，要求每条直线上不能出现两个或以上的棋子。(The classical data structure problem Eight queens problem.Question is placed on the 8* 8 board piece, requirements on each line cannot appear two or more pieces.)

使用非递归的方法遍历二叉树，可以直接运行。( Non-recursive binary tree traversal.)

读取数据，统计所得到的文件中每个字母的权值，创建哈夫曼树，哈夫曼编码。哈夫曼解码，解码后内容写入到指定的文件。 读取数据里面的内容是由英文单词组成。读取文件的时候传入文件存放的路径、读取方式以及读出以后存放的数组，最终可以得到一个存放目标文件内容的数组。 将得到的数组进行字母权值的统计，统计每个字母出现的次数，次数即为每个字母的权值。 将得到的字符数组与权值数组作为创建哈夫曼树的依据，哈夫曼树根据每个字母权值的大小来创建，每个节点，包括权值、父节点、左子、右子和字母本身。 根据哈夫曼树进行编码。形成目标文件的哈夫曼编码，将此编码返回。 根据哈夫曼树得到的数组即为解码数组，解码数组作为解码的结果返回。 写入输出文件，将解码得到的数组、文件的完整路径以及文件的写方式作为参数传入，将数组写入到相应的文件中。 (Read the data, statistical documents obtained weights for each letter, create a Huffman tree, Huffman coding. Huffman decoding, the decoded contents are written to the specified file. Read the content inside is composed of English words. When the incoming file to read the file storage path, read mode and read out after storage array that can eventually get a storage target file contents of the array. The resulting array of letter weights statistics, statistical number of occurrences of each letter, the number is the weight of each letter. The resulting character array with the weights array as the basis for creating Huffman tree, Huffman tree based on the size of the weights of each letter to create, for each node, including weights, parent, left child, right child, and letter itself. According to Huffman coding. The formation of the target file Huffman coding, this code returns. According to Huffman decoding the resulting array is an array, the decoder decodes the result is retur)

校园导航系统包含佛山科技学院本部校区的校园景点平面图。通过系统的各功能不仅可以查询任意景点的编号，名称，简介等信息，还可以查询任意两景点间的最短路径及长度和所有路径及长度。另外，还可以通过一系列操作增加，更改或删除任意的景点的各信息。(Contains the campus attractions plan of the campus Foshan Institute of Technology campus navigation system. Through the function of the system not only can query any spots number, name, profile and other information, can also query the shortest path and arbitrary length between two spots and all paths and the length of. In addition, can also increase through a series of operations, the information change or delete any of the attractions.)

魔方问题 数据结构 使用c++ 经典问题(Cube problem Data Structure Using c++ Classic problem)