DIJKSTRA算法实现的最短路径程序linjiebiaoshortpath

数据结构，利用霍夫曼树实现文本数据的压缩。(Huffman data compression and decompression.)

用链表解决约瑟夫问题。 约瑟夫环是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。 其中包括一个实验报告，介绍了编程思路和输出结果截图。(List to resolve Joseph. Josephus is the application of a mathematical problem: Given n individuals (numbered 1, 2, 3, ... n, respectively) sitting around a round table around. From number k people began to count off the number to m the man out of the line his next person and from a number off, the man was out of the line number to m so regularly repeated down until roundtable around of the people all of the columns. Including a lab report describes the programming ideas and output screenshots.)

说明：  线性表的基本运算及多项式的算术运算在顺序表泪SeqList 中增加成员函数void Reverse()实现顺序表的逆置 (Linear form the basic arithmetic operations and the polynomial form in order to increase tear SeqList member function void Reverse () to achieve the inverse order of the table set)

通过c语言数组算法解决josephus问题，m个人围成一圈，从第一个小孩开始顺时针方向每数到第n个小孩时这个小孩离开，最后剩下的小孩是胜利者。求第几个小孩为胜利者(C language array algorithm to solve the Josephus problem, m individual circle, from the first child began to count clockwise every n children, the child left, and finally the remaining child is the winner. A few kids for victory)

说明：  数据隐私保护K-匿名问题的动态多次发布类似m-invarience算法(Data Privacy Protection K-anonymity problem on many occasions issued a similar dynamic m-invarience algorithm)

为了点分 求分下载好麻烦 c++二叉排序树(In order to find points dotted download good trouble c++ binary sort tree)

约瑟夫环的循环链表实现，这个程序比较完整，有需要做试验的请速速下载。(Josephus cycle Chain achieved, the procedure is complete, the pilot needs to be done urgently requested to download.)

几个比较好的初级算法，初学者可以看一下思想，对算法入门(A few good elementary algorithms, beginners can look at thinking on algorithms entry)

使用C语言完成党的霍夫曼编码，主要使用树的数据结构，作为巩固数据结构的练习(Using the C language to complete the party' s Huffman coding, the main use of the tree data structure, data structure as a consolidation exercise)

一个简单的停车场管理程序,是初级学习数据结构时的一个十分重要的实验,了解这个对学习堆栈十分有用,基本题目是 设有一个可以停放[size=10.5pt]N[size=10.5pt]辆汽车的狭长的停车场，[size=10.5pt] [size=10.5pt]它们有一个大门可以供车辆进出。车辆按到达停车场时间的先后次序从停车场最里面向门口处停放（最先到达的第一辆车停在停车场的最里面）。如果停车场已放满[size=10.5pt]N[size=10.5pt]辆车，则后来的车辆只能在停车场大门外的便道上等待，一旦停车场内有车开走，则排在便道上的第一辆车就可进入停车场。停车场内如果有某辆车要开走，在它之后进入停车场的车辆都必须先退出停车场为它让路，待其开出停车场后，这些车辆再依原来的次序进入。每辆车在离开停车场时，根据它在停车场内停留时间的长短交费。如果停在便道上的车辆未进入停车场就要离去，允许其离去时不收停车费，并且仍然保持在便道上等待的车辆的次序()