-
icp2
ICP version 2. Removes one to many correspondences.
- 2012-04-28 02:41:38下载
- 积分:1
-
mimomo
its a matlab program ~~~~~ you can do tit
- 2012-04-30 15:59:32下载
- 积分:1
-
1
说明: 基于matlab的模块化通信系统仿真设计,以及实验报告(this is a design of engineer system modulation based on matlab2012b)
- 2013-08-30 16:49:34下载
- 积分:1
-
shahoodamax
this is a code for ECG signal analysis i wish you modify before using
- 2013-03-15 22:39:22下载
- 积分:1
-
MATLAB
matlab 经典例题解析,大家多多支持,多多分享
(matlab)
- 2010-10-29 16:08:35下载
- 积分:1
-
shipsimulation
一个很好的船舶仿真源程序,希望对大家有用。(Simulation of a good source of the ship, in the hope that useful.)
- 2009-05-09 15:07:53下载
- 积分:1
-
Optimization_Newton
设r是f(x) = 0的根,选取x0作为r初始近似值,过点(x0,f(x0))做曲线y = f(x)的切线L,L的方程为y = f(x0)+f (x0)(x-x0),求出L与x轴交点的横坐标 x1 = x0-f(x0)/f (x0),称x1为r的一次近似值。过点(x1,f(x1))做曲线y = f(x)的切线,并求该切线与x轴交点的横坐标 x2 = x1-f(x1)/f (x1),称x2为r的二次近似值。重复以上过程,得r的近似值序列,其中x(n+1)=x(n)-f(x(n))/f (x(n)),称为r的n+1次近似值(Let r is f (x) = 0 root, select the initial approximation x0 as the r, over point (x0, f (x0)) to do the curve y = f (x) the tangent L, L the equation y = f ( x0)+ f ' (x0) (x-x0), find the intersection of L and the x-axis of abscissa x1 = x0-f (x0)/f' (x0), x1 is called an approximation r. Through points (x1, f (x1)) to do the curve y = f (x) the tangent, and find the intersection of the tangent with the x-axis of abscissa x2 = x1-f (x1)/f ' (x1), x2 is called r the second approximation. Repeat the process, get an approximation of the sequence r, where x (n+1) = x (n)-f (x (n))/f ' (x (n)), as an approximation of r n+1 times)
- 2011-06-21 21:13:09下载
- 积分:1
-
harr-face
this is a harr classifier for frontal face
- 2015-02-09 18:39:34下载
- 积分:1
-
3
对一个矩阵进行Cholesky分解的matlab程序(the cholesky decomposition of one matrix)
- 2014-01-06 19:51:12下载
- 积分:1
-
matlabandVC01
精通matlab与c+c++混合程序设计+第2版_,PDF格式,还算清晰,刘维编著,有兴趣的朋友可以下载下来看看 共三卷 (Proficient in matlab and c+ c++ mixed programming+ version 2 _, PDF format, fairly clear, Liu Wei, ed, interested to see if friends can download down)
- 2010-09-06 20:59:37下载
- 积分:1