matlab-nihe

自己编写的 混洗蛙跳算法优化最小二乘支持向量机参数 把文件里的数据、LSSVM模型更换，就可以移植(written by Son.Y.M Shuffled frog leaping algorithm to optimize the parameters of LS-SVM The data in the file, LSSVM model replacement, you can transplant)

灰色模型预测是在数据不呈现一定规律下可以采取的一种建模和预测方法，其预测数据与原始数据存在一定的规律相似性 下面程序是灰色模型GM(1,1)程序二次拟合和等维新陈代谢改进预测程序,matlab6.5 ,使用本程序请注明，程序存储为gm1.m(Gray model prediction is a kind of modeling and forecasting method which can be taken under certain regularity of data. The prediction data has some regular similarity with the original data The following procedure is the gray model GM (1,1) program quadratic fit and isometric metabolic improvement prediction program, matlab6.5, use this procedure please specify that the program is stored as gm1.m)

说明：  含有积分算法 依据光场分布的积分算法，使用积分算法计算探测面某点的光强 利用高斯光场的分布，计算不同探测角度的光强分布(Integral algorithm. The integral algorithm is used to calculate the light intensity of a point on the detection surface by integral algorithm.. The distribution of Gauss light field is used to calculate the intensity distribution of different detection angles.)

说明：  C与C++ 语言中表达式的求值，主要讲解了副作用及顺序点的概念(C and C++ language expression evaluation, the main points to explain the concept of side effects and the order of)

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统计信号处理-Fundamentals of Statistical Singal Processing习题答案(Statistical Signal Processing-Fundamentals of Statistical Singal Processing Exercises answer)

ladder filter synthesis

A composite microgrid model along with statcom.

说明：  filter size image processing

Converts a floating point value to IEEE 754 32 bit binary representation. Sign Bit: 1 Exp: 2 to 9 Frac: 10:32 Single-precision floating-point format is a computer number format that occupies 4 bytes (32 bits) in computer memory and represents a wide dynamic range of values by using a floating point. In IEEE 754-2008 the 32-bit base 2 format is officially referred to as binary32. It was called single in IEEE 754-1985. In older computers, other floating-point formats of 4 bytes were used. For example, the 32-bit floating point bit pattern 1 01111101 00101100000000000000000 is interpreted as the following: (− 1)1 × (1 + 0.34375) × 2(125–127) = -1.34375× 2− 2 = -0.3359375 ​