Simulation-of-dendritic-growth

说明：  c编写的链表连接函数，上课时学的，上传试试 (c write the list to connect function, class, learn, try uploading)

USACO中的American heritage，用C++编写，运用了树的遍历知识(the American heritage of USACO, with C++ prepared, using a tree traversal knowledge)

哈希表 数据结构课程设计 1.1问题描述 针对自己的班集体中的“人名”设计一个哈希表，使得平均查找长度不超过R，完成相应的建表和查表程序。 1.2基本要求 假设人名为中国姓名的汉语拼音形式。待填入哈希表的人名共有30个，取平均查找长度的上限为2。构造哈希函数，用链表法处理冲突。 1.3测试数据 读取熟悉的30个人的姓名作测试。(Hash table Data Structure Course Design 1.1 Description of the problem For their own class group of the "names" to design a hash table, making the average search length does not exceed R, the completion of construction of tables and look-up table corresponding procedures. 1.2 Basic requirements Assuming the name of the person called Chinese pinyin form. To be filled into a hash table names a total of 30, taking the average search length of the upper limit of 2. Construct a hash function, treatment with a list of conflict. 1.3 Test Data Read the familiar names of 30 individuals tested.)

约瑟夫环（约瑟夫问题）是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1，最后结果+1即为原问题的解。 (Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)

实现冒泡，快速，希尔排序法。并计算，比较他的次数。(Achieve bubbling fast shell sort. And calculate, compare the number of times.)

选择排序的实现，是一种基本的排序方法，但是时间复杂度相对较大。(Select Sort realization, is sort of a basic, but relatively large time complexity.)

长整数四则运算,利用双向循环链表实现长整数的存储，每个结点含一个整形变量。 (Long integer arithmetic, the use of two-way circular linked list to achieve long integer storage, each node contains an integer variable.)

堆栈实现C++,以VC++环境为准——逍遥大洋至上(The stack of the C++, VC++ environment will prevail)

数据结构基础内容，两栈共享空间，参考《大话数据结构》(Structural basis of data content, two stacks shared space, refer to Westward data structure )

双向链表 清华大学 出版社 《数据结构 C++》 源代码实现(Tsinghua University Press doubly linked list <data structure, C++> source code)