lianbiao

说明：  给定程序中，函数fun的功能是：将a所指3×5矩阵中第k列的元素左移到第0列，第k列以后的每列元素依次左移，原来左边的各列依次绕道右边。 例如，有以下矩阵： 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 若k结果为2，程序执行结果为： 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 请在程序的下划线处填入正确的内容并把下划线删除，使程序得出正确的结果。 注意：源文件存放在考生文件夹下的BLANK1.C中 不得增行或删行，也不得更改程序的结构！ (A given program, function fun feature is: a 3 × 5 matrix referred to in the first k elements of the left column to move Section 0, the k elements of each column after column followed by the left, the original columns in the left turn Bypass on the right. For example, the following matrix: 123,451,234,512,345 If k is 2, the program execution results: 345,123,451,234,512 in the program underscore the right content at the fill and to remove the underscore, so that the program reach the right result. Note: The source files in the folder of BLANK1.C candidates are not allowed by the line or delete line, nor change the structure of the program!)

约瑟夫环（约瑟夫问题）是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1，最后结果+1即为原问题的解。 (Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)

分析汉诺塔，选择合适方法编程实现汉诺塔问题的解答。(Analysis of the Tower of Hanoi, select the appropriate method of programming the answers of the Tower of Hanoi problem.)

题意:给你n个数,求出两两组合的最大公约数 类似打素数表的做法 (Meaning of the questions: to give you the number n, find greatest common divisor of a similar combination twenty-two hit the practice table of prime numbers)

这个程序用来解决树结构与树之间的程序匹配的问题这个程序可以解决很多的问题(it is very good)

读取数据，统计所得到的文件中每个字母的权值，创建哈夫曼树，哈夫曼编码。哈夫曼解码，解码后内容写入到指定的文件。 读取数据里面的内容是由英文单词组成。读取文件的时候传入文件存放的路径、读取方式以及读出以后存放的数组，最终可以得到一个存放目标文件内容的数组。 将得到的数组进行字母权值的统计，统计每个字母出现的次数，次数即为每个字母的权值。 将得到的字符数组与权值数组作为创建哈夫曼树的依据，哈夫曼树根据每个字母权值的大小来创建，每个节点，包括权值、父节点、左子、右子和字母本身。 根据哈夫曼树进行编码。形成目标文件的哈夫曼编码，将此编码返回。 根据哈夫曼树得到的数组即为解码数组，解码数组作为解码的结果返回。 写入输出文件，将解码得到的数组、文件的完整路径以及文件的写方式作为参数传入，将数组写入到相应的文件中。 (Read the data, statistical documents obtained weights for each letter, create a Huffman tree, Huffman coding. Huffman decoding, the decoded contents are written to the specified file. Read the content inside is composed of English words. When the incoming file to read the file storage path, read mode and read out after storage array that can eventually get a storage target file contents of the array. The resulting array of letter weights statistics, statistical number of occurrences of each letter, the number is the weight of each letter. The resulting character array with the weights array as the basis for creating Huffman tree, Huffman tree based on the size of the weights of each letter to create, for each node, including weights, parent, left child, right child, and letter itself. According to Huffman coding. The formation of the target file Huffman coding, this code returns. According to Huffman decoding the resulting array is an array, the decoder decodes the result is retur)

包含了数据结构实现堆栈的方法。 主要有链表实现和数组实现以及堆栈的应用。(This pakcet inclues the programs to implement the stack with chain and array and it s application.)

说明：   简单的链表实现 链表可以初步了解(A simple list can be linked to achieve a preliminary understanding)

简单的迷宫问题，有点土，还望大家多指点指点，在此感激不尽。(????? mad spasm, ? Tang Gao, ? oligonucleotide ??? Ning Ning ? ?, Hitomi ?????.)

斐波那契堆是一种具有较好平摊时间的堆数据结构。我使用C语言来实现斐波那契堆。(Fibonacci heap is a heap of time with good flat data structure. I am using C language to implement Fibonacci heap.)