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moni
数据结构 银行模拟问题 (Bank of simulation data structure problem)
- 2011-01-04 21:08:10下载
- 积分:1
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sort.cpp
各种排序的模板实现,并分析了各种实现的时间复杂度及改进办法(Templates of various sort, and analyze the time complexity of the various implementations and ways to improve)
- 2012-04-14 03:08:18下载
- 积分:1
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BinaryTree
c++数据结构中的二分查找树,是比较基本的数据查找结构,查找效率比较高(c++ data structure in the binary search tree, is a more basic data to find the structure to find more efficient)
- 2009-10-31 20:04:38下载
- 积分:1
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text
输入N个点的坐标,判断这N个点能否构成一个凸多边形。(Enter the coordinates of N points, to determine whether the N points form a convex polygon.)
- 2011-12-13 09:43:42下载
- 积分:1
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Data.Structures.For.Game.Programmers
说明: 详细介绍了游戏设计的数据结构注意事项,对与游戏中角色和游戏模式作者给予了督导的见解,书中语言为全英文但通俗易懂!很是推荐
(Data.Structures.For.Game.Programmers
Detailed data structure of the game design considerations, the role with the game and game modes of supervision given to insights, the book in English but the language is easy to understand! It is recommended)
- 2010-04-14 11:21:09下载
- 积分:1
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AVLTree
好用的平衡二叉树类库,C++类库编写,
好用的平衡二叉树类库,C++类库编写(AVL tree implementation for C++)
- 2009-03-12 12:02:05下载
- 积分:1
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zhebanchazhao
实现折半查找,非递归形式,从而实现数据结构所要的结果。(To achieve binary search, the non-recursive form)
- 2012-08-29 12:35:25下载
- 积分:1
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Z
说明: 在给定的字母中,用c++来实现字母的排序(In a given letter, the use of c++ to implement the letter of the sort)
- 2010-06-29 21:59:50下载
- 积分:1
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maze
迷宫求解一般采用“穷举法”,逐一沿顺时针方向查找相邻块(一共四块-东(右)、南(下),西(左)、北(上))是否可通,即该相邻块既是通道块,且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)
- 2013-12-13 17:55:45下载
- 积分:1
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HuffanCoding
读取数据,统计所得到的文件中每个字母的权值,创建哈夫曼树,哈夫曼编码。哈夫曼解码,解码后内容写入到指定的文件。
读取数据里面的内容是由英文单词组成。读取文件的时候传入文件存放的路径、读取方式以及读出以后存放的数组,最终可以得到一个存放目标文件内容的数组。
将得到的数组进行字母权值的统计,统计每个字母出现的次数,次数即为每个字母的权值。
将得到的字符数组与权值数组作为创建哈夫曼树的依据,哈夫曼树根据每个字母权值的大小来创建,每个节点,包括权值、父节点、左子、右子和字母本身。
根据哈夫曼树进行编码。形成目标文件的哈夫曼编码,将此编码返回。
根据哈夫曼树得到的数组即为解码数组,解码数组作为解码的结果返回。
写入输出文件,将解码得到的数组、文件的完整路径以及文件的写方式作为参数传入,将数组写入到相应的文件中。
(Read the data, statistical documents obtained weights for each letter, create a Huffman tree, Huffman coding. Huffman decoding, the decoded contents are written to the specified file.
Read the content inside is composed of English words. When the incoming file to read the file storage path, read mode and read out after storage array that can eventually get a storage target file contents of the array.
The resulting array of letter weights statistics, statistical number of occurrences of each letter, the number is the weight of each letter.
The resulting character array with the weights array as the basis for creating Huffman tree, Huffman tree based on the size of the weights of each letter to create, for each node, including weights, parent, left child, right child, and letter itself.
According to Huffman coding. The formation of the target file Huffman coding, this code returns.
According to Huffman decoding the resulting array is an array, the decoder decodes the result is retur)
- 2020-07-02 15:40:01下载
- 积分:1