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单链表逆置的源码~提供了源码和源码说明~简单实用，适用于课堂作业程度(Reverse single linked list provides a set of source code source code and source code ~ ~ simple and practical instructions for classroom work degree)

本代码主要实现了哈希表的设计，完成了哈希函数的相关要求。(The code is designed to achieve a hash table, the completion of the relevant requirements of the hash function.)

这个是数据结构课程设计中阿黄的CD的程序代码的工程文件包(This is a data structure curriculum design A yellow CD program code works package)

说明：  进程死锁.资源分配图的绘制 建立所需数据结构；  使用题目21存成的资源分配图的文件作为输入；  编写资源分配图化简算法；  每化简一步，在屏幕上显示化简的当前结果；  最后给出结论，是否死锁，如思索给出死锁的进程及资源； (Process deadlock. Resource allocation mapping  establish the required data structures  Use title 21 deposit into resource allocation graph file as input  writing resource allocation map simplification algorithm  Each simplification step, on-screen display simplification of the current result  Finally, the conclusion of a deadlock, deadlock is given as thinking processes and resources )

POJ 字符串的插入 可以将一定长度的字符串插入之前给出的字符串之中(POJ string can be inserted into a length of string into a string before being given)

阿当姆斯显式和隐式求解方法，用四阶龙格库塔作为起始，然后运用四阶阿当姆斯算法求解初值问题。主要程序包含在test2.cpp中，方法简单易懂。编译环境VC2010(Adam James explicit and implicit method for solving fourth-order Runge-Kutta as a start, then use the fourth-order A Williams algorithm for solving initial value problem. The main program contains in test2.cpp method is simple and easy to understand. Compile environment VC2010)

一道poj上的问题的解答，棋盘上的距离问题。即实现棋盘上从一个点移动到王，后，兵之间最短步数的解答。(A poj answers to your questions on the chessboard distance problem. That is, move from one point to the king on the board, after the shortest number of steps between the soldiers answer.)

通过学习奥赛培训课程，利用回溯加递归的编程技巧完成的迷宫问题(Training courses through learning Orsay, plus use of recursive programming skills back to complete the maze problem)

为了点分 求分下载好麻烦 c++二叉排序树(In order to find points dotted download good trouble c++ binary sort tree)

数据结构课程作业，查找算法。用哈希算法下实行查找(Data structure course work, search algorithm. Under the hash algorithm used to find)