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参加运动会的 个学校编号为 。比赛分成 个男子项目和 个女子项目，项目编号分别为 和 。由于各项目参加人数差别较大，有些项目取前五名，得分顺序为7，5，3，2，1；还有些项目只取前三名，得分顺序为5，3，2。写一个统计程序产生各种成绩单和得分报表。 2、要求产生各学校的成绩单，内容包括各校所取得的每项成绩的项目号、名次（成绩）、姓名和得分；产生团体总分报表，内容包括校号、男子团体总分、女子团体总分和团体总分。 3、测试数据：对于 ， ， ，编号为奇数的项目取前五名，编号为偶数的项目取前三名，设计一组实例数据。 (The school serial number participating in Games is. Competition divides into men s event and women s event , the project serial number parts for the sum. The difference is bigger since every project participates in a number , some projects choose the first five , score order is 7 , 5 , 3 , 2 , 1 Still have some of projects taking the first three places , score only being 5 , 3 , 2 in proper order. Write a form for report counting procedure producing the various school report card and score. 2, demands the school report card producing every school , content includes every achievement project number , position in a name list (achievement) , full name and score per got by school Produce the group total points form for report , content including the school number , male person group total points , woman group total points and group total points. 3, testing data: Be that the odd number project chooses the first five to the serial number, the serial number is that the even number project c)

使用全排列实现hash，看看吧相信对大家会有些帮助的(Full array hash)

实现冒泡，快速，希尔排序法。并计算，比较他的次数。(Achieve bubbling fast shell sort. And calculate, compare the number of times.)

主要用栈和树求解骑士问题，用C++语言编写的(The main stack and tree Cavalier Problem Solving with C++ languages)

关于二叉树的一些相关代码，运用链表的形式，求二叉树的高度，结点个数以及叶节点个数(Some of the relevant code on the binary tree, using a linked list, find the height of a binary tree, the number of nodes, and the number of leaf nodes)

数据结构作业－停车场管理(operating data structure-the car park management)

通过c语言数组算法解决josephus问题，m个人围成一圈，从第一个小孩开始顺时针方向每数到第n个小孩时这个小孩离开，最后剩下的小孩是胜利者。求第几个小孩为胜利者(C language array algorithm to solve the Josephus problem, m individual circle, from the first child began to count clockwise every n children, the child left, and finally the remaining child is the winner. A few kids for victory)

实验内容： 建立一个包含图书（书号，书名，定价）信息的的链表，并具有如下功能： (1) 根据指定图书个数，逐个输入图书信息； (2) 根据书名进行查找，返回此书的书号和定价； (3) 根据指定的位置可返回相应的图书信息（书号，书名，定价）； (4) 给定一个图书信息，插入到表中指定的位置； (5) 删除指定位置的图书记录； (6) 统计表中图书个数。 (It is a good c++.)

数字根算法，用最简单的代码计算数字根。如果把一个大数的各位数字相加得到一个和，再把这个和的各位数字相加又得一个和，再继续作数字和，直到最后的数字和是个位数为止，这最后的数称为最初那个数的“数字根”。(Digital root algorithm, with the most simple code to calculate the digital root. If you figure in a large numbers is the sum of a, then this and you figure the sum is again a, and then continue for digital and until the final figure and the single digits, the last number called initially that the number of "digital root".)

本程序解决的是：模拟类似计算机主、缓存的存储结构，当用户请求某个页面时，若某个页面已在缓存中，则直接从缓存中去取，不会产生失误（即未在缓存中命中），否则，就到主存中去取，代价变大。 本程序采用随机标记算法，即在在线标记算法的基础上，对于替换页面时，采用随机从未标记的缓存项中选出一项进行替换。 代码、文档详尽(Addressed in this program are: analog computer-like main, cache storage structure, when the user requests a page, a page in the cache directly from the cache to fetch, does not produce errors (that is, not in the cache in the hit), otherwise, to the main memory to fetch a consideration of larger. This program uses a random marking algorithm, online marking algorithm based on random never mark the cache entry selected a replacement for the replacement page. Code, documentation detailed)