登录
首页 » Visual C++ » DouglasPeucker

DouglasPeucker

于 2011-08-28 发布 文件大小:35KB
0 282
下载积分: 1 下载次数: 29

代码说明:

  道格拉斯—普克法(Douglas—Peucker)的C++程序(Douglas- Puck method (Douglas-Peucker) of the C++ program)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • arc
    运用二叉树求代数表达式的值,将代数表达式的每个符号用二叉树结点表示,遍历图的每一结点,按结点值得不同采用不同运算方式(Solving algebraic expressions binary tree)
    2012-06-23 19:52:38下载
    积分:1
  • 插入排序
    根据所选定的字符顺序,按照从大到小的规则,对字符进行插入排序,(Insert and sort characters)
    2020-06-22 12:40:01下载
    积分:1
  • CarClass
    数据结构简单的课程设计交通换乘算法,里面有零次换乘与一次换乘(Simple structure, curriculum design data traffic transfer algorithm, which have zero time transfer and a transfer)
    2011-01-09 10:33:14下载
    积分:1
  • StackandQueue
    该ppt包含了栈和队列的数据结构及基本操作,同时还有栈的举例(This ppt contains the stack and queue data structure and basic operation, as well as examples of the stack)
    2013-12-06 21:02:24下载
    积分:1
  • Tic-tac-toe-chess
    C语言实现井字棋博弈的过程,采用极大极小算法。(The C language game of tic-tac-toe chess, using the minimax algorithm.)
    2012-05-20 23:15:48下载
    积分:1
  • jhgrerfgjz
    一个简单的求矩阵求逆的c语言算法 一个简单的求矩阵求逆的c语言算法 一个简单的求矩阵求逆的c语言算法(a simple matrix inversion for the C language algorithms for a simple matrix inversion of the c language a simple algorithm The matrix inversion for the C language algorithms for a simple matrix inversion algorithm in C Language)
    2021-03-29 11:39:11下载
    积分:1
  • d
    有助于c++的初学者在平日的学习中更好的学习(Contribute to better learning c++ beginners learning on weekdays)
    2013-11-29 14:32:18下载
    积分:1
  • Work3.5
    上海交通大学数据结构课程的课后作业系列3.5:仅供参考,最好还是自己去写(Shanghai Jiaotong University data structure course homework Series 3.5: for reference, it is best to write their own)
    2013-12-27 21:00:03下载
    积分:1
  • 约瑟夫环的循环链表实现
    约瑟夫环的循环链表实现,这个程序比较完整,有需要做试验的请速速下载。(Josephus cycle Chain achieved, the procedure is complete, the pilot needs to be done urgently requested to download.)
    2005-07-03 19:38:38下载
    积分:1
  • Cpp1
    校园导游,可以选择景点序号来了解景点,通过选择两点可计算最短距离和最近路线。(Campus tour guide, you can choose the attractions serial number to understand the attractions of by selecting the shortest distance can be calculated and the recently routes.)
    2012-06-20 21:57:32下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载