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GenPoly_matric
利用线性移位寄存器序列的线性关系,用求解矩阵的方法求解移存器序列的生成多项式(get LFSR sequence prime Polynomial by the line relationship of the sequence )
- 2009-12-29 16:28:28下载
- 积分:1
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pumidu
谱密度的计算 用于水文时间序列的周期分析(Cycle analysis of the calculation of the spectral density for hydrological time series)
- 2012-06-03 10:21:10下载
- 积分:1
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apply_iframe
24 Dec 2008
Suhasini
Please provide us in English it will be great help if you can do this for us
01 May 2008
Rostom Mabrouk
Goog job
19 Mar 2008
Muhammad Fahim
Please any body tells me about english comments to understand this or any other useful link for such type of code.
19 Feb 2008
Gustavo Meschino
Please, try to translate to English!
This GUI seems to be very useful, but I can t understand the function of buttons.
31 May 2007
Joshua Z
I use the FCMClust core, good stuff!
21 Apr 2007
rose RED
est ce que vous pouvez m expliquer le code matlab de segmentation par la methode FCM
MERCI
29 Jan 2007
Karthik T Raja
Y no reply for me
- 2013-04-30 21:08:41下载
- 积分:1
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fx
说明: 地震勘探的必备工具。大家相互交流,请专业方面的朋友多多指教!(An indispensable tool for seismic exploration. U.S. mutual exchanges, please professional exhibitions Friend!)
- 2007-10-28 15:41:20下载
- 积分:1
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PMSM-Drive-Simulation-Files
drive of pmsm with vector control
- 2014-11-21 18:37:52下载
- 积分:1
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AWGN_Simulation
本程序仿真了高斯噪声的几种概率密度估计方法(This procedure simulated several Gaussian noise probability density estimation method)
- 2015-02-06 16:47:11下载
- 积分:1
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Lyapunov_Lorenz
基本原理就是首先求解出连续系统微分方程的近似解,然后对系统的Jacobian矩阵进行QR分解,计算Jacobian矩阵特征值的乘积,最后计算出LE和分数维(The basic principle is to first find the approximate solution of differential equations continuous system, then the system will be on the Jacobian matrix QR decomposition product Jacobian matrix computing eigenvalues, and finally calculate the fractal dimension LE)
- 2021-03-12 20:09:24下载
- 积分:1
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波束空间MUSIC算法源程序
基于波束空间的MUSIC多重信号分类算法源程序(MUSIC algorithms based on beam forming)
- 2020-07-10 16:18:55下载
- 积分:1
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BPSO-FS
说明: binary particle swarm optimization for features selection
- 2021-02-17 15:40:13下载
- 积分:1
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antcolony
该程序试图对具有31个城市的VRP进行求解,已知的最优解为784.1,(The program attempts to have 31 cities to solve VRP, known optimal solution for the 784.1,)
- 2008-05-14 21:26:08下载
- 积分:1