labyrinth

二叉树的先序遍历。采用递归实现。释放资源时用了后序遍历。(Preorder traversal of a binary tree. Recursive implementation. Release resources used after preorder.)

计算点到直线的距离．输入两点坐标确定一个直线，再输入一个点的坐标，计算该点到直线的距离．(Calculated point to the straight line distance. Enter the coordinates of two points determine a straight line, and then input the coordinates of a point, to calculate the straight-line distance between points.)

POJ 字符串的插入 可以将一定长度的字符串插入之前给出的字符串之中(POJ string can be inserted into a length of string into a string before being given)

说明：  c编写的链表连接函数，上课时学的，上传试试 (c write the list to connect function, class, learn, try uploading)

说明：  进程死锁.资源分配图的绘制 建立所需数据结构；  使用题目21存成的资源分配图的文件作为输入；  编写资源分配图化简算法；  每化简一步，在屏幕上显示化简的当前结果；  最后给出结论，是否死锁，如思索给出死锁的进程及资源； (Process deadlock. Resource allocation mapping  establish the required data structures  Use title 21 deposit into resource allocation graph file as input  writing resource allocation map simplification algorithm  Each simplification step, on-screen display simplification of the current result  Finally, the conclusion of a deadlock, deadlock is given as thinking processes and resources )

约瑟夫环（约瑟夫问题）是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1，最后结果+1即为原问题的解。 (Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)

数据结构中基于约瑟夫环问题，用C++方式实现的。。。。。(Data structure based on Josephus problem with C++ a manner. . . . .)

Monkeys and peach,Monkeys and peach(Monkeys and peach)

输入N个点的坐标，判断这N个点能否构成一个凸多边形。(Enter the coordinates of N points, to determine whether the N points form a convex polygon.)

简单选择排序，这是个解决排序问题的一个算法模型之一。(Sort simple choice, this is a solution to a scheduling problem, one algorithm model.)