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数据结构经典算法 约瑟夫问题 c++ 已经测试通过(josephus c++)

the longest common serials

经典的 数据结构问题 八皇后问题。问题是在8*8的棋盘上放置棋子，要求每条直线上不能出现两个或以上的棋子。(The classical data structure problem Eight queens problem.Question is placed on the 8* 8 board piece, requirements on each line cannot appear two or more pieces.)

数据挖掘中聚类算发中基于密度的算法DBSCAN(Hair count data mining clustering algorithm DBSCAN density-based)

上海交通大学数据结构课程的课后作业系列3.5：仅供参考，最好还是自己去写(Shanghai Jiaotong University data structure course homework Series 3.5: for reference, it is best to write their own)

用c++实现的haffman tree 小程序，仅供参考 。 (The the haffman tree applet realized with c++ for reference only.)

说明：  分别用堆栈和数组的方法实现任何进制的数制转换(Arrays were used to stack and method of implementation of any binary number system conversion )

假设要在足够多的会场里安排一批活动，并希望使用尽可能少的会场。设计一个有效的贪心算法进行安排。（这个问题实际上是著名的图着色问题。若将每一个活动作为图的一个顶点，不相容活动间用边相连。使相邻顶点着有不同颜色的最小着色数，相应于要找的最小会场数。） 对于给定的k 个待安排的活动，编程计算使用最少会场的时间表。 (Suppose you want to arrange a number of activities in the hall more than enough, and want to use as little as possible venue. Design an effective greedy algorithm arrangements. (This problem is actually well-known graph coloring problem. If each activity as a vertex map, with the side connected between incompatible activities. Makes coloring adjacent vertices with minimum number of different colors, corresponding to looking The minimum number of venue.) K to be arranged for a given activity, calculated using a minimum of venue programming schedule.)

数据结构 堆栈 实现了以下功能： cout<<"----------------主菜单---------------"<<endl <<"* 1.建立 *"<<endl <<"* 2.输出 *"<<endl <<"* 3.判断栈是否为空 *"<<endl <<"* 4.栈的长度 *"<<endl <<"* 5.输出栈顶元素 *"<<endl <<"* 6.进栈 *"<<endl <<"* 7.出栈 *"<<endl <<"* 8.遍历 *"<<endl <<"* 9.数制转换 *"<<endl <<"* 10.清空 *"<<endl <<"* 11.销毁 *"<<endl <<"* 12.退出 *"<<endl <<"--------------------------------------"<<endl<<endl (data structure stack)

　广度优先搜索及深度优先搜索，用C语言实现，比较使用(Breadth-first search and depth first search, using C language, compared with)