string.tar

单链表中的数据元素含有三种字符（字母、数字、其他字符），算法实现构造三个循环链表，是每个循环链表中只含有同一类字符，且利用原表中的结点空间作为这三个表的结点空间。(Singly linked lists of data element contains three characters (letters, Numbers and other characters), the algorithm constructs three circular linked list, each cycle list contains only the same type of character, and make use of the primary node space in a table as a node of the three table space.)

中科大数据结构全部上机实验的实验程序以及报告，内容包括多项式，图，栈，SQL语言……(All experimental procedures USTC data structures as well as reports on experiments, including polynomial, maps, stack, SQL language ......)

组合数学全排列,包含有六种全排列的方法，字典序法(math of permutations)

航迹起始中的逻辑航迹起始算法源代码，本代码具有很好的航迹起始效果！ (Track initiation logic for track initiation algorithm source code, this code has the effect of track initiation)

简单选择排序，这是个解决排序问题的一个算法模型之一。(Sort simple choice, this is a solution to a scheduling problem, one algorithm model.)

按照一定的输入求出二叉树的层次遍历，输出相应的结果(Calculated in accordance with the input binary tree traversal of the hierarchy, the output of the corresponding results)

利用栈完成算术表达式求值：从键盘或文件中输入算术表达式，计算其结果并显示。要求处理过程为：（1）转换为后缀表达式并输出；（2）对后缀表达式求值并输出。 输入的表达式中可以有整数、实数、括号，运算符包括+、-、*、/、#（代表单目负）。可以多次输入不同的表达式进行计算，直到用户选择“退出”。栈的基本操作可以自己实现，也可以使用系统提供的STL实现。 (Done using an arithmetic expression evaluation stack: file input from the keyboard or an arithmetic expression, calculate and display the results. Requirements process: (1) to postfix expression and output (2) evaluation of the postfix expression and output. Enter the expression can be integers, real numbers, parentheses, operators including+,-,*,/,#( representatives unary minus). You can enter several different expressions are evaluated until the user selects " Exit." Stack can implement the basic operations, you can also use the system implementation of the STL.)

纯C语言写的小型通用数据库，一个C数据结构组科技小组的作品，附有开发思路PPT，这可是一个宝贵的资源哦，更底层的东西，运行于DOS提示符，可以新建数据库等操作。C的编程高手们值得参考一下。 (Pure C language to write a small general-purpose database, a data structure C Group Technology Group works to develop ideas with PPT, this is a valuable resource Oh, and the bottom of things, running on the DOS prompt, you can operate a new database. C programming masters worthy of reference.)

校园导航系统包含佛山科技学院本部校区的校园景点平面图。通过系统的各功能不仅可以查询任意景点的编号，名称，简介等信息，还可以查询任意两景点间的最短路径及长度和所有路径及长度。另外，还可以通过一系列操作增加，更改或删除任意的景点的各信息。(Contains the campus attractions plan of the campus Foshan Institute of Technology campus navigation system. Through the function of the system not only can query any spots number, name, profile and other information, can also query the shortest path and arbitrary length between two spots and all paths and the length of. In addition, can also increase through a series of operations, the information change or delete any of the attractions.)

校园导航问题，设计你的学校的平面图，至少包括10个以上的景点（场所），每两个景点间可以有不同的路，且路长也可能不同，找出从任意景点到达另一景点的最佳路径（最短路径）。 要求： （1）以图中顶点表示校园内各景点，存放景点名称、代号、简介等信息；以边表示路径，存放路径长度等有关信息。 （2）为来访客人提供图中任意景点相关信息的查询。 （3）为来访客人提供任意景点的问路查询，即查询任意两个景点之间的一条最短路径。 （4）修改景点信息。 (Campus navigation problem, the design of your school s plan, at least more than 10 attractions (places), between every two spots can have a different way, and the long road may be different, to find spots to reach from any other attractions best path (shortest path). Requirements: (1) graph vertices represent various campus sites, storage sites name, code, profile and other information the side that path, the path length of storage of information. (2) the figure for visiting any sites offering information about the query. (3) any attractions for visiting guests ask queries of that query any two of the shortest path between sites. (4) modify the attractions information.)