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说明：  子集和数问题.rar，用C++写的，可以运行(Subset of several problems. Rar, written in C++, you can run)

上海交通大学数据结构课程的课后作业系列3.5：仅供参考，最好还是自己去写(Shanghai Jiaotong University data structure course homework Series 3.5: for reference, it is best to write their own)

说明：  进程死锁.资源分配图的绘制 建立所需数据结构；  使用题目21存成的资源分配图的文件作为输入；  编写资源分配图化简算法；  每化简一步，在屏幕上显示化简的当前结果；  最后给出结论，是否死锁，如思索给出死锁的进程及资源； (Process deadlock. Resource allocation mapping  establish the required data structures  Use title 21 deposit into resource allocation graph file as input  writing resource allocation map simplification algorithm  Each simplification step, on-screen display simplification of the current result  Finally, the conclusion of a deadlock, deadlock is given as thinking processes and resources )

C++实现的两类问题随机森林生成算法，对学习随机森林很有帮助(Source code for random forests,wanderful codes,and help youself to it!)

VC简易通讯录，加强C的编程，熟悉链表文件的使用等。(Simple VC contacts, strengthen C programming, familiar with the use of a linked list file.)

二叉树的操作，涉及到三种顺序的遍历，树的凹入表示法，转化为一维数组储存，节点的计数，以及中序线索化。(Binary operation, involving three kinds of the order of traversal, tree concave representation into a one-dimensional array of storage, the node count, as well as in the threaded sequence.)

/*快速排序：以待排序元素中的第一个元素作为基准将带排序的元素分为三组 *大于基准元素为一组置于基准值的右边，小于基准值的元素为一组置于基准值的左边， *基准值为一组，这样就找到了基准元素的位置就确定了 *如此递归调用。直到每一组的low==high，即实现了排序的要求。 */ (/* Rapid Sort: the first element to be sorted in the element as a basis with with sorting the elements are divided into three groups* is greater than the reference element of a group is placed on the right side of the reference value, smaller than the reference value elements for a group of placed on the left side of the reference value,* reference value, a group, so that the location of the reference element is found it is determined* so recursive call. Until each group of low == high to achieve the requirements of the sort.* /)

数据结构与程序设计中的重点例子程序：八皇后问题(Data structure and procedures of the focus of the design example of the procedure: eight queen problem)

用链表解决约瑟夫问题。 约瑟夫环是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。 其中包括一个实验报告，介绍了编程思路和输出结果截图。(List to resolve Joseph. Josephus is the application of a mathematical problem: Given n individuals (numbered 1, 2, 3, ... n, respectively) sitting around a round table around. From number k people began to count off the number to m the man out of the line his next person and from a number off, the man was out of the line number to m so regularly repeated down until roundtable around of the people all of the columns. Including a lab report describes the programming ideas and output screenshots.)

设计一个表达式求值的程序。该程序必须可以接受包含（，），+，-，*，/的中缀表达式，并求出结果。如果表达式正确，则输出表达式的结果；如果表达式非法，则不输出或输出其他字符。(Design an expression evaluation procedures. The program must accept (,), including +, -, *, / the infix expression, and the results obtained. If the expression is correct, the output of the expression is output; if the expression is illegal, no other characters are output or exported.)